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cestrela7 [59]
3 years ago
13

Look at photo D. Explain how the fountains help to keep the gardens cool. ​

Physics
1 answer:
Anton [14]3 years ago
7 0

Answer with Explanation:

Spain is known to have <em>hot summers</em>, thus, it is very easy for water to evaporate once exposed to<u> direct heat source</u> (such as the sun).

A fountain is being used in order to keep the garden's surrounding air temperature low by allowing the<u><em> evaporation of water</em></u><u>.</u> One factor that speeds up the evaporation of water is the<u> surface area</u>. The water coming out of a fountain is in small quantities; however, it meets up with hot air in a<em> large surface area.</em> This allows faster evaporation, leading to an even <em>greater cooling effect because heat is being transported immediately from the liquid state to the gaseous state.</em> This is the reason why people often meet up in places where there's a fountain. It is not only aesthetically appealing but also<em><u> provides comfort from the hea</u></em>t.

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A long string carries the wave; a segment of the string measuring 6.00 meters in length and weighing 180 grams contains four full wavelengths. The string vibrates sinusoidally at a 50.0 Hz frequency with a 15.0 cm peak-to-valley displacement. The vertical distance between the farthest positive and negative positions is known as the "peak-to-valley" distance. The function that describes this wave traveling in the positive x direction is y=(7.50 \mathrm{~cm}) \sin \left(\frac{4 \pi}{3} \times-314 t+\phi\right).

\begin{aligned}& f=500 \mathrm{~Hz} \\&\mu=\frac{180 \times 10^{-3}}{6}=3 \times 10^{-2} K g / m \\&2 A=15 \times 10^{-2} m \\&A=7.5 \times 10^{-2} m \\&4 \lambda=6, \lambda=3 / 2 m \text {. and } v=f \lambda=75 m / \mathrm{sec} \\&\omega=2 \pi f=100 \pi \text { also } K=\frac{\omega}{v}=\frac{4 \pi}{3}\end{aligned}

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$\therefore$ equation is $y=7.5 \times 10^{-2} \sin \left[100 \pi t-\frac{4 \pi}{3} x+\phi\right]$

∴ equation is y=(7.50 \mathrm{~cm}) \sin \left(\frac{4 \pi}{3} \times-314 t+\phi\right)

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