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3 years ago

Is magnesium carbonate soluble in water

Chemistry

2 answers:

KiRa [710]3 years ago

8 0

Magnesium carbonate can do this because it doesn't dissolve in water, only acid, where it will effervesce (bubble).

seropon [69]3 years ago

5 0

Answer:

no it is not, it is only soluable in acid.

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20.00 g of aluminum (Al) reacts with 78.78 grams of molecular chlorine (Cl2), all of each reaction is completely consumed and as

shepuryov [24]

The reaction forms 98.76 g AlCl_3.

We have the masses of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.

M_r: ___26.98 _70.91 __133.34

________2Al + 3Cl_2 → 2AlCl_3

Mass/g: 20.00 _78.78

Step 2. Calculate the moles of each reactant

Moles of Al = 20.00 g Al × (1 mol Al /26.98 g Al) = 0.741 29 mol Al

Moles of Cl_2 = 78.78 g Cl_2 × (1 mol Cl_2 /70.91 g Cl_2) = 1.11 10 mol Cl_2

Step 3. Identify the limiting reactant

Calculate the moles of AlCl_3 we can obtain from each reactant.

From Al: Moles of AlCl_3 = 0.741 29 mol Al × (2 mol AlCl_3/2 mol Al) = 0.741 29 mol AlCl_3

From Cl_2: Moles of AlCl_3 = 1.11 10 mol Cl_2 × (2 mol AlCl_3/3 mol Cl_2) = 0.740 66 mol AlCl_3

Cl_2 is the limiting reactant because it gives the smaller amount of AlCl_3.

Step 4. Calculate the mass of AlCl_3.

Mass = 0.740 66 mol AlCl_3 × 133.34 g/1 mol AlCl_3 = 98.76 g AlCl_3

The reaction produces 98.76 g AlCl_3.

4 0

3 years ago

How many moles of oxygen gas can 0.882 mol of hydrogen peroxide produce if decomposition is complete? 2H2O2 (l) → 2H2O(l) + O2(g

andreyandreev [35.5K]

We are given the chemical reaction and the amount of reactant used for the process. We use these data together to obtain what is asked. We do as as follows:

0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced

Hope this answers the question.

5 0

4 years ago

Read 2 more answers

You unknowingly run over a small nail while driving and it punctures your tire. When you are getting in your car the next mornin

Norma-Jean [14]

The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.

<h3>What is effusion?</h3>

Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.

When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.

Therefore, option c. a punctured tire deflates due to effusion.

Learn more about effusion here:

brainly.com/question/2823560

#SPJ1

7 0

2 years ago

A container of 56mL is at STP, The pressure is increased to 3.6atm and the volume to 162 mL.

Sindrei [870]

Answer:

T2 = 2843.1 oK. This is a huge temperature. Check it for errors.

Explanation:

Remark

This is the same question as the other one I've answered. Only the numbers have been altered.

Givens

v1 = 56 mL

P1 = 1 atm

T1 = 273o K

v2 = 162

P2 = 3.6 atm

T2 = ?

Formula

Vi * P1 / T1 = V2 * P2/T2

Solution

Rearrange the formula so T2 is on the left

T2 = V2 P2 * T1 / (V1 * P1) Now just put the numbers in.

T2 = 162 * 3.6* 273 / (56 *1)

T2 = 159213.6/56

T2 = 2843.1

3 0

3 years ago

PLEASE SOMEBODY EXPLAIN THIS :(((

djverab [1.8K]

Answer:

$\boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}$

<h3>Explanation:</h3>

In Analytical Chemistry chromatography is widely used for the separation of samples.

In thin layer chromatography, the mixture of components are separated on the basis of their polarity.
The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.
Consider the mixture we have taken consist of two samples having large polar difference.
Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.
The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.

In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.

Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.

Formula to calculate Rf value is

$\sf R_f \: value = \frac{distance \: moved \: by \: sample}{distance \: moved \: by \: solvent}$

Now, solving for Rf value of sample 1

Given:

Distance moved by sample 1 = 11 mm

Distance movedby solvent = 35 mm

To find:

Rf value of sample 1 = ?

Solution:

Substituting the given data in above formula,

$\small \sf R_f \: value = \frac{distance \: moved \: by \: sample \: 1}{distance \: moved \: by \: solvent} \\ \small \sf R_f \: value = \cancel\frac{11 \: mm}{35 \: mm} = 0.3142$

$\small \boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}$

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4 0

2 years ago