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Black_prince [1.1K]
4 years ago
10

What are two different kinds of rock that are easily weathered by carbonic acid?

Chemistry
1 answer:
horsena [70]4 years ago
8 0
Limestone and marble are the two rocks that are easily weathered by carbonic acid. Two kinds of weathering mostly affect the rocks. and they are physical weathering and chemical weathering. The above mentioned two rocks are highly affected by carbonic acid. The appeareance of these kind of rocks change their structure due to erosion very regularly. Caronation is the type of chemical weathering that affects the rocks limestone and marble. The carbonic acide is formed by the reaction of carbon dioxide in the air and water in the rivers. This carbonic acid results in weathering.
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The Kp for the reaction below is 1.49 × 108 at 100.0°C:CO(g) + Cl2(g) → COCl2(g)In an equilibrium mixture of the three gases, PC
Serggg [28]

<u>Answer:</u> The equilibrium partial pressure of phosgene is 7.34 atm

<u>Explanation:</u>

The given chemical equation follows:

                    CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The expression of K_p for above equation follows:

K_p=\frac{p_{COCl_2}}{(p_{CO})\times (p_{Cl_2})}

We are given:

Equilibrium partial pressure of CO = 2.22\times 10^{-4}atm

Equilibrium partial pressure of chlorine gas = 2.22\times 10^{-4}atm

K_p=1.49\times 10^8

Putting values in above equation, we get:

1.49\times 10^8=\frac{p_{COCl_2}}{(2.22\times 10^{-4})\times (2.22\times 10^{-4})}\\\\p_{COCl_2}=7.34atm

Hence, the equilibrium partial pressure of phosgene is 7.34 atm

7 0
3 years ago
Iodine has many isotopes, but only iodine-127 is stable and is found in nature. One
Lemur [1.5K]
Iodine has 53 protons. For question 82, the number 127 stands for neutrons plus protons. So the neutron for I-127 is 74. For 83, according to the definition of isotopes, they need to have the same number of protons and different number of neutrons. I-127 and I-131 satisfy these requirements. For 85, the half life of I-131 is 8 days which means after 8 days, only half of sample remains unchanged. So if 80 gram change to 1.25 gram, it goes through 6 half life. So it took 48 days.
3 0
3 years ago
mixture of 75 cm3of oxygen and 12.5 cm3 of a gaseous hydrocarbon H were exploded in an eudiometer. After cooling to room tempera
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Answer:

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Explanation:

Computation of the amount of oxygen that reacts .

⇒ 75 - 12.5

⇒ 62.5 cm³

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2 mole hydrocarbons 3n+1 oxygen

⇒ 3 n + 1 = [62.5 × 2] / 12.5

⇒ 3 n + 1 = 10

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So,

Formula of the hydrocarbon is C₃H ₈

Computation of molar mass of C₃H ₈

⇒ [12×3] + [1×8]

⇒ 44 g/mole

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Compare and contrast the characteristics of metals and nonmetals.
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