Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected. Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.
Answer:
11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Explanation:
Chloroacetic acid is an monoprotic acid.
Neutralization reaction: 
So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.
Molar mass of chloroacetic acid = 94.5 g/mol
So, 0.154 g of chloroacetic acid = 
moles of chloroacetic acid
= 0.00163 moles of chloroacetic acid
Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.
So, number of moles of NaOH needed to reach equivalence point
= 
moles
So, 
or, V = 11.6
Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Answer: mg(OH)2 = +37
Rbl = 31
RbOH= -83
mgl2= -144
Explanation: just did it on edge2020
All halogens are stable so they have 8 electrons in their last shell
the compound with the smaller lattice energy is potassium sulphide here the size of the molecule play a important role
The quantity of energy released by the electrostatic attraction of oppositely charged ions is known as lattice energy (L.E). The ion's size and charge affect the lattice energy.
lattice energy is inversely proportional to size of ion and directly proportional to charge of the ion. They are each charged equally that is plus two and minus two However, because the Sulphur is larger in size and the oxygen is lesser in this case, The lattice energy of potassium oxide is larger the lattice energy of potassium sulphide is smaller.
To learn more about lattice energy :
brainly.com/question/18222315
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