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Arisa [49]
3 years ago
8

Which of the following is not a double-replacement?

Physics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

The correct answer is option D.

Explanation:

From the given options the reaction which is not a double replacement reaction is:

Zn (s) + 2HCl (aq)\rightarrow H_2 (g) + ZnCl_2 (s)

This because the above reaction is an example of single replacement reaction.

AB+C\rightarrow AC+B

Whereas;

Double replacement reaction is a type of chemical reaction in which exchange of ions among the reactants take place.

AB+CD\rightarrow AD+CB

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11. A collection of a small group of factors that are related is known as a(n)
malfutka [58]

Answer:

system

Explanation:

they are all put together as one, and they are a group

5 0
2 years ago
A single insulated duct flow experiment using air operating at steady-state is performed in a lab. One measurement location (Sta
weqwewe [10]

Answer:

a) -0.0934 kJ/kg. K

b) The direction of flow is from right to left.

Explanation:

A free flow diagram of the horizontal insulated duct is as shown below.

NOW,

Let assume that the direction of flow is from left to right and consider the following relation for the entropy rate balance equation for a control volume as:

\frac{\sigma_{cv}}{m}= (s_2-s_1) \geq  0 \ \ \ -------> \ \ \ 1

Now; if the value for this relation is greater than zero; then we conclude that our assumption is correct.

If the value is less than zero; then we conclude that the assumption is wrong.

Then, the flow is said to be  in the opposite direction

Formula for the change in specific entropy can be calculated as:

s_2-s_1 = s^0(T_2) - s^0(T_1)-R \ In ( \frac{P_2}{P-1}) \ \ \  ------->  \ \ \ 2

where;

s_1, s_2 , s^0(T_2), s^0(T1) are specific entropies

R = universal gas constant

P_1 = pressure at location 1

P_2 = pressure at location 2

We obtain the specific properties of air at temperature at T_1 = (67°C + 273)K = 340 K from the table A-22 ( Ideal gas properties of air)

s^0(T1) = 1.8279 kJ/kg.K

We also obtain the specific properties of air at temperature T_2 = 22°C + 273) K = 295 K

From the table A- 22

s^0(T_2) = 1.68515 kJ/kg . K

R = \frac{8.314 kJ}{28.97 kg.K}

P_1 = 0.95 bar

P_2 = 0.8 bar

Now replacing our values  into equation (2) from above; we have;

s_2-s_1 = s^0(T_2) -s^0(T_1)-R \ In (\frac{P_2}{P_1} )

s_2-s_1 = 1.68515 -1.8279-\frac{8.314}{28.97}  \ In (\frac{0.8}{0.95} )

s_2-s_1 = 1.68515 -1.8279+ 0.0493

s_2-s_1 =-0.0934 \  kJ/kg.K

Equating our result to equation (1)

s_2-s_1 \geq 0\\-0.0934 \leq 0

Therefore , our assumption is wrong and the direction of flow is said to be from right to left.

We therefore conclude that the direction of flow is from right to left.

3 0
3 years ago
Someone can help me pls <br><br> Is physical science class
pentagon [3]

Answer:

<em> I can't see the picture</em>

Explanation:

6 0
3 years ago
Chapter 16, Problem 63. A person is standing in a room at 18 ◦C. The exposed surface area and skin temperature of the person are
Juliette [100K]

Answer:Q=248.011 W

Explanation:

Given

Temperature of Room T_{\infty }=18^{\circ}\approx 291 K

Area of Person A=1.7 m^2

Temperature of skin T=32^{\circ}\approx 305 K

Heat transfer coefficient h=5 W/m^2.k

Emissivity of the skin and clothes \epsilon =0.9

\Delta T=32-18=14^{\circ}

Total rate of heat transfer=heat Transfer due to Radiation +heat transfer through convection

Heat transfer due radiation Q_1=\epsilon \sigma A(T^4-T_{\infty }^4 )

where \sigma =stefan-boltzman\ constant

Q_1=0.9\times 5.687\times 10^{-8}\times 1.7\times (305^4-291^4)

Q_1=129.01 W

Heat Transfer due to convection is given by

Q_2=hA(\Delta T)

Q_2=5\times 1.7\times 14=119 W

Q=Q_1+Q_2

Q=129.01+119=248.011 W

7 0
3 years ago
Am arrow of mass 1000kg is shot into a wooden block of mass 5000lg lying at rest in a smooth surface.If the arrow travels 15m/s
Ber [7]

Answer:

Vf=3

Explanation:

you must first write your data

data before impact

M1=1000 M2=5000

V1=0 m/s V2 =0m/s

data after impact

M1=1000 M2=5000

V1=15m/s V2=?

M1V1 +M2V2=M1V1 +M2V2f

(1000)(0)+(5000)(0)=(1000)(15)+(5000)Vf

0=15000+5000Vf

- 15000÷5000=5000Vf÷5000

Vf= -3

Vf =3

6 0
2 years ago
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