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soldi70 [24.7K]
3 years ago
5

Which statement best compares the momentum of a 5-kilogram fish swimming at a speed of 10 meters/second and a 2-kilogram fish sw

imming at a speed of 10 meters/second?
Physics
2 answers:
ruslelena [56]3 years ago
6 0
M = mass of the larger fish =5kg
<span>V = velocity of the larger fish =10m/s</span>
<span>m = mass of the smaller fish =2kg</span>
<span>v = velocity of the smaller fish =10m/s
</span>formula=
<span>MV = mv 
5kg*10m/s=2kg*10m/s
biggern mass fish has more momentum
hope this helps

</span>
Ronch [10]3 years ago
5 0

Answer:

The momentum of the 5-kilogram fish is greater than the momentum of the 2-kilogram fish

Explanation:

The momentum of each fish can be calculated as follows:

p=mv

where

m is the mass of the fish

v is the velocity of the fish

- For the first fish, we have:

p=mv=(5 kg)(10 m/s)=50 kg m/s

- For the second fish:

p=mv=(2 kg)(10 m/s)=20 kg m/s

Therefore, the momentum of the first fish is greater than the second fish.

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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It would be 'when they have like charges.'

'Like charges' means the same charge. For example, two positive charged objects have like charges.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

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4 0
3 years ago
Uma carga puntiforme de + 3,0uC é colocada em um ponto P de um campo elétrico gerado por uma partícula eletrizada com carga desc
expeople1 [14]

Responda:

1) E = 6 × 10 ^ 6NC ^ -1 2) Q = 6 × 10 ^ -5

Explicação:

Dado o seguinte:

Carga (q) = 3uC = 3 × 10 ^ -6C

Força elétrica (Fe) = 18N

Intensidade do campo elétrico (E) =?

1)

Lembre-se:

Força elétrica (Fe) = carga (q) * Intensidade do campo elétrico (E)

Fe = qE; E = Fe / q

E = 18N / (3 × 10 ^ -6C)

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2)

Lembre-se:

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r = distância de espera = 30cm = 30/100 = 0,3m

K = 9,0 × 10 ^ 9

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Answer:

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Answer:

im sure your already past this but it's E.

Explanation:

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