Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
The equation of c is an illustration of subject of formula
The equation of c in terms of r and t is c = r - 15/t
<h3>How to determine the equation?</h3>
The equation is given as:
t = 15/(r - c)
Cross multiply
t(r - c) = 15
Divide both sides by t
r - c = 15/t
Subtract r from both sides
-c = -r + 15/t
Multiply both sides by -1
c = r - 15/t
Take LCM

Hence, the equation of c in terms of r and t is 
Read more about subject of formula at:
brainly.com/question/10643782
Answer:
The center is [-1,-2
Step-by-step explanation:
Say, length =x mileWidth =. x/5 milex*x/5=9/2020x*x=45x*x=45/20 =9/4x=3/2 mileLength =3/2 milesWidth=. 3/10 miles