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shusha [124]
3 years ago
15

Why are so many large optical telescopes located on mountaintops

Physics
2 answers:
postnew [5]3 years ago
8 0
Avoid cloud and man-made lights
Ivahew [28]3 years ago
3 0
Because light is degraded when it has to pass through air.

The best places for large telescopes would be on the Moon, in space,
or in orbit (like the Hubble, Kepler, and Webb space telescopes). 

If you can't manage any of those places, or can't afford them, then
the next best choice for a location is any place where the light doesn't
need to plow through a lot of air to reach your telescope.  Those places
are either on top of mountains or under giant helium balloons.  Both of
these ideas have been used extensively for the past 100 years.
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An atom with 4 protons, 5 neutrons, and 4 electrons has an atomic mass of _____ amu. (Enter a whole number.)
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Atomic mass = number of protons + number of neutrons = 4+5 = 9 amu
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Help me yall it due in a few minutes :((()
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B. blocks 2 & 3.

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Block 1 has equal & opposite forces acting on it.

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3 years ago
If the angle of reflection is 25 degrees, the angle of incidence is
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7 0
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A sample of carbon dioxide (C°p,m = 37.11 J K−1 mol−1) of mass 2.80 g at 27°C is allowed to expand reversibly and adiabatically
My name is Ann [436]

Answer:

182 to 3 s.f

Explanation:

Workdone for an adiabatic process is given as

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

where γ = ratio of specific heats. For carbon dioxide, γ = 1.28

For an adiabatic process

P₁V₁ʸ = P₂V₂ʸ = K

K = P₁V₁ʸ

We need to calculate the P₁ using ideal gas equation

P₁V₁ = mRT₁

P₁ = (mRT₁/V₁)

m = 2.80 g = 0.0028 kg

R = 188.92 J/kg.K

T₁ = 27°C = 300 K

V₁ = 500 cm³ = 0.0005 m³

P₁ = (0.0028)(188.92)(300)/0.0005

P₁ = 317385.6 Pa

K = P₁V₁¹•²⁸ = (317385.6)(0.0005¹•²⁸) = 18.89

W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)

V₁ = 0.0005 m³

V₂ = 2.10 dm³ = 0.002 m³

1 - γ = 1 - 1.28 = - 0.28

W =

18.89 [(0.002)⁻⁰•²⁸ - (0.0005)⁻⁰•²⁸]/(-0.28)

W = -67.47 (5.698 - 8.4)

W = 182.3 = 182 to 3 s.f

7 0
3 years ago
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