Answer:
The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.
Explanation:
The kinetic energy
of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.
The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy
of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.
Answer:
option a is correct
Explanation:
<h2>I hope it's help you ❣️❣️</h2>
Answer:
The velocity of the frozen rock at
is -14.711 meters per second.
Explanation:
The frozen rock experiments a free fall, which is a type of uniform accelerated motion due to gravity and air viscosity and earth's rotation effect are neglected. In this case, we need to find the final velocity (
), measured in meters per second, of the frozen rock at given instant and whose kinematic formula is:
(Eq. 1)
Where:
- Initial velocity, measured in meters per second.
- Gravity acceleration, measured in meters per square second.
- Time, measured in seconds.
If we get that
,
and
, then final velocity is:
![v = 0\,\frac{m}{s}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (1.5\,s)](https://tex.z-dn.net/?f=v%20%3D%200%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%2B%5Cleft%28-9.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%20%5Ccdot%20%281.5%5C%2Cs%29)
![v = -14.711\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%20-14.711%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
The velocity of the frozen rock at
is -14.711 meters per second.
She does 200J .
We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)