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Fantom [35]
3 years ago
8

Hanna tosses a ball straight up with enough speed to remain in the air for several seconds?

Physics
2 answers:
olga_2 [115]3 years ago
3 0
A) the velocity is 0 m/s
Lorico [155]3 years ago
3 0

Answer:

Explanation:

In the free fall motion we have that the acceleration is constant and produced by gravity, this acceleration has a magnitude of 32 ft/s2 or 9.8 m/s2 depending on the units you are working with. This means that every second the speed changes a magnitude of 32 ft/2, the velocity will depend of whether the ball is going upward (positive) or downward (negative).

A) At the highest point the ball stops to start the descend, here v=0 ft/s

B) +32 ft/s. The vector is going up, in the next second the velocity is going to be 0 (negative acceleration)

C) V=vf-vo=0-32=-32 ft/s is the constant change in velocity in projectile motion

D) -32 ft/s. The vector is pointing downward

E)  V=vf-vo=-32-0=-32 ft/s is the constant change in velocity in projectile motion, 32 ft/s per second

F) Delta V=vf-vo=-32-32=-72 ft/s

g) gravity acceleration is constant 32 ft/s2 (pointing downward vector)

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Two radio antennas are 120 m apart on a north-south line, and they radiate in phase at a frequency of 3.4 MHz. All radio measure
chubhunter [2.5K]

Answer:

the smallest angle from the antennas is <em>47.3°</em>

Explanation:

We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.

Therefore, the relation is:

λ = c /f

where

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  • λ is the wavelength
  • f is the frequency

Thus,

λ = (3 × 10⁸ m/s) / (3.4 MHz)

  = (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)

  = 88.235 m

Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as

θ = sin⁻¹(λ / d)

where

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Thus,

θ = sin⁻¹(88.235 / 120)

<em>θ = 47.3 °</em>

<em></em>

Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is <em>47.3 °</em>.

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3 years ago
What is the concentration of H+ ions at a pH = 7? mol/L What is the concentration of OH– ions at a pH = 7? mol/L What is the rat
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<h3><u>Answer;</u></h3>

= 0.0000001 mol/L  

= 0.0000001 mol/L  

= 1:1

<h3><u>Explanation;</u></h3>

What is the concentration of H+ ions at a pH = 7?

The formula for ph is given by:

pH=−log10[H+]

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pH+pOH=14

7+pOH=14

pOH= 7

[OH-]=(10)^(-pOH)

[OH-]=(10)^(-7)

<u>= 0.0000001 mol/L  </u>

What is the ratio of H+ ions to OH– ions at a pH = 7?  

1:1

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