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larisa86 [58]
2 years ago
5

What is the maximum distance that a 60.-watt motor may vertically lift a 90.-newton?weight in 7.5 seconds?a. 2.3mb. 5.0mc. 140md

. 1100m
Physics
1 answer:
Naddik [55]2 years ago
5 0

Answer:

b. 5.0 m

Explanation:

Power: Power can be defined as the rate at which work is done.

The S.I unit of power is watt (W).

P = W/t ............................................... Equation 1

Where p = power, W = work, t = time.

But

W = F×d..................................... Equation 2

Where F = force, d = maximum distance.

Substituting equation 2 into equation 1

P = F×d/t

making d the subject of the equation above,

d = Pt/F......................................................... Equation 3

<em>Given: F = 90 Newton, P = 60 watt, t = 7.5 seconds.</em>

<em>Substituting these values into equation 3,</em>

<em>d = 60×7.5/90</em>

<em>d = 5 m</em>

Thus the maximum distance is = 5 m

The right option is b. 5.0 m

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lbvjy [14]

Answer:

201.6 N

Explanation:

m = mass of disk shaped merry-go-round = 125 kg

r = radius of the disk = 1.50 m

w₀ = Initial angular speed = 0 rad/s

w = final angular speed = 0.700 rev/s = (0.700) (2π) rad/s = 4.296 rad/s

t = time interval = 2 s

α = Angular acceleration

Using the equation

w = w₀ + α t

4.296 = 0 + 2α

α = 2.15 rad/s²

I = moment of inertia of merry-go-round

Moment of inertia of merry-go-round is given as  

I = (0.5) m r² = (0.5) (125) (1.50)² = 140.625 kgm²

F = constant force applied

Torque equation for the merry-go-round is given as

r F = I α

(1.50) F = (140.625) (2.15)

F = 201.6 N

4 0
3 years ago
A bus traveling at 24 m/s slows down to 12 m/s in 5.0 seconds. What is the acceleration?
Contact [7]

Answer:

a = -2.4 m/s²

Explanation:

Given,

The initial speed of the bus, u = 24 m/s

The final speed of bus, v = 12 m/s

Time taken to reach final speed is, t = 5.0 s

The acceleration of the body is given by the change in velocity by time

                                      a = (v - u) / t

                                         = (12 - 24) / 5

                                         = -2.4 m/s²

The negative sign in the acceleration indicates that the bus is decelerating.

Therefore, the acceleration of the bus is, a = -2.4 m/s²

8 0
2 years ago
A runner begins running at the beginning of 7th period and stops running at the end of the period. She runs at a pace of 10 km/h
MrRissso [65]

Answer:

She run for, t = 0.92 s

Explanation:

Given data,

The velocity of the runner, v = 10 km/h

The distance covered by the runner, d = 9.2 km

The relationship between the velocity, displacement and time is given by the formula,

                           t = d / v

Substituting the given values in the above equation,

                           t = 9.2 / 10

                             = 0.92 s

Hence, she ran for, t = 0.92 s

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Answer:

answer 3

Explanation:

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