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larisa86 [58]
3 years ago
5

What is the maximum distance that a 60.-watt motor may vertically lift a 90.-newton?weight in 7.5 seconds?a. 2.3mb. 5.0mc. 140md

. 1100m
Physics
1 answer:
Naddik [55]3 years ago
5 0

Answer:

b. 5.0 m

Explanation:

Power: Power can be defined as the rate at which work is done.

The S.I unit of power is watt (W).

P = W/t ............................................... Equation 1

Where p = power, W = work, t = time.

But

W = F×d..................................... Equation 2

Where F = force, d = maximum distance.

Substituting equation 2 into equation 1

P = F×d/t

making d the subject of the equation above,

d = Pt/F......................................................... Equation 3

<em>Given: F = 90 Newton, P = 60 watt, t = 7.5 seconds.</em>

<em>Substituting these values into equation 3,</em>

<em>d = 60×7.5/90</em>

<em>d = 5 m</em>

Thus the maximum distance is = 5 m

The right option is b. 5.0 m

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Two clear but non-mixing liquids each of depth 15 cm are placed together in a glass container. The liquids have refractive indic
murzikaleks [220]

Answer:

A. 19.8 cm.

Explanation:

The apparent depth of the combination is

As it mentioned that the two clear but non-mixing liquid having depth of 15 cm that placed in a glass container together

Also the refractive indices would be 1.75 and 1.33

Based on the above information

As we know that

Refractive indices = real depth ÷ apparent depth

1.33 ÷ 1.75 = 15  ÷ apparent depth

So, it would be 19.736842 cm

Now the combination of apparent depth would be

= ( 19.736842 + 15) ÷ (1.75)

= 19.8 cm

hence, the correct option is A.

4 0
3 years ago
Par 1/2
BaLLatris [955]

part 1

mass = ρ x V

mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg

PE (potential energy)= mgh

PE = 6608.2 kg x 9.81 x 403

PE = 2.61 x 10⁷ J

part 2

megaton of TNT (Mt) =4.2 x 10¹⁵ J

convert PE to Mt:

2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt

4 0
3 years ago
the initial velocityof a particle along x axis is u at t=0 x=0 and its acceleration is given by a =2x then whats the correct equ
miskamm [114]

Answer:

v² = u² + 2x²

Explanation:

v² = u² + 2as​ is only valid for constant acceleration.  Here, the acceleration is a function of position.  We can find the function of velocity by integrating.  Acceleration is the derivative of velocity with respect to time:

a = 2x

dv/dt = 2x

Apply chain rule:

dv/dt = dx/dt × dv/dx

dv/dt = v × dv/dx

Therefore:

v dv/dx = 2x

Separate the variables and integrate:

v dv = 2x dx

½ v² |ᵤᵛ = x² |₀ˣ

½ (v² − u²) = x²

v² − u² = 2x²

v² = u² + 2x²

8 0
3 years ago
If the average velocity of a duck is zero in a given time interval, what can you say about the displacement of the duck for that
Gemiola [76]

Answer:

Also 0

Explanation:

Since average speed of an object is that object's displacement over a unit of time, when an average speed is 0, its displacement over a unit of time must also be 0. When an average speed is not 0, then its displacement over a unit of time is also not 0 for that interval.

6 0
3 years ago
A car traveled 330 miles in 6 hours. What is the average speed?
shusha [124]

it is 55 mph that is ok


6 0
3 years ago
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