Question

Find the work w1 done on the block by the force of magnitude f1 = 65.0 n as the block moves from xi = -3.00 cm to xf = 3.00 cm .

Answer 1

W = F•dx
F = 65 N,
dx = xf - xi = 0.03 m - (-0.03 m) = 0.06 m
W = 65 N × 0.06 m = 3.9 J