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3 years ago

Which is not true about the pH scale?

Physics

2 answers:

pochemuha3 years ago

4 0

Answer:

The pH scale was invented by Svante Arrhenius is false.

Explanation :

because the pH scale was invented by Soren Sorensen

tester [92]3 years ago

3 0

Hello school i points are the correct spelling.

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A ball of mass 0.440 kg moving east (+x direction) with a speed of 3.80 m/s collides head-on with a 0.220-kg ball at rest. If th

avanturin [10]

Answer:

The speed and direction of each ball after the collision is 1.27 m/s to East direction and 5.07 m/s to East direction.

Explanation:

given information

m₁ = 0.440 kg

v₁ = 3.80 m/s

m₂ = 0.220 kg

v₂ = 0

collision is perfectly elastic

v₁ - v₂ = - (v₁'- v₂')

v₁ = - (v₁'- v₂')

v₂' = v₁ + v₁'

according to momentum conservation energy

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

m₁v₁ = m₁v₁' + m₂(v₁ + v₁')

m₁v₁ = m₁v₁' + m₂v₁ + m₂v₁'

m₁v₁ - m₂v₁ = m₁v₁' + m₂v₁'

v₁ (m₁ - m₂) = (m₁ + m₂) v₁'

v₁' = (m₁ - m₂)v₁ / (m₁ + m₂)

= (0.440 - 0.220) (3.8) / (0.440 + 0.220)

= 1.27 m/s to East direction

v₂' = v₁ + v₁'

= 3.8 + 1.27

= 5.07 m/s to East direction

4 0

3 years ago

8. A tortoise moves a distance of 100 metres in 15 minutes. What is the average speed of

myrzilka [38]

Answer: 0.4 km/h

100 m = 0.1 km
15min./60min. = 0.25 hr

so, divide the total distance (100 m) by the total time (15 min)
0.1 km/0.25 hr = 0.4

8 0

3 years ago

A salt shaker sits 0.102 m from

Ivahew [28]

The maximum speed is 0.55 m/s

Explanation:

For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:

$\mu_s mg = m\frac{v^2}{r}$

where the term on the left is the frictional force and the term on the right is the centripetal force, and where

$\mu_s$ is the coefficient of static friction

m is the mass of the body

g is the gravitational acceleration

v is the speed of the body

r is the radius of the circular path

In this problem, we have:

$\mu_s = 0.307$

r = 0.102 m

$g=9.8 m/s^2$

Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:

$v=\sqrt{\mu gr}=\sqrt{(0.307)(9.8)(0.102)}=0.55 m/s$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0

3 years ago

A 1-lb block and a 100-lb block are placed side by side at the top of a frictionless hill. Each is given a very light tap to beg

qwelly [4]

Answer:

(c). The two blocks end in a tie

Explanation:

the reason being the absence of any resistance offered to both of the blocks.

if the slope of the hill is for instance 60 deg.

then the acceleration in absence of any resistance is a= 9.81sin(60)

since the acceleration is same then both of the blocks will reach at the same instant

4 0

4 years ago

Please help me Calculate the total energy stored in the capacitor

Neko [114]

La fórmula: P = W/t ó W = P x t. donde:

P = potencia

W = trabajo

t = tiempo

Otra fórmula de potencia es: P= I x V

Proceso de carga de un capacitor - condensador

Una fórmula muy importante que también hay que tener en cuenta es: V = q/C que indica que el voltaje es proporcional a la carga que hay en un condensador.

De la fórmula de potencia P= I x V y considerando que la corriente es constante (corriente continua), entonces la potencia es proporcional al voltaje. Si el voltaje aumenta en forma lineal, la potencia aumentará igual. Ver el siguiente diagrama.

Como la potencia varía en función del tiempo, no se puede aplicar la fórmula W = P x t, para calcular la energía transferida. Pero observando el gráfico, se ve que esta energía se puede determinar midiendo el área bajo la curva de la figura.

Energía Almacenada en un Condensador - Capacitor

El área bajo la curva es igual a la mitad de la potencia en el momento “t”, multiplicada por “t”.

Entonces: W = (P x t) / 2. Pero se sabe que P = V x I. Si se reemplaza esta última fórmula en la anterior se obtiene: W = (V x I x t) / 2, y como I x t = CV = Q, entonces para saber cuanta energía (W) hay en un condensador usamos una de las siguientes fórmulas:

W = (CV2/2) julios

W = (QV/2) julios

W = (Q2/2C) julios

, donde:

W = Trabajo (Energía) en julios

C = Capacidad en faradios

V = voltaje en voltios en los extremos del condensador

Q = carga del condensador

3 0

3 years ago

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