It will increase blood
pH. This is because pCO2 also reduces. pCO2 is critical in the <span>maintenance of blood pH. Dissolved CO2 from respiring
tissues dissolves in blood to form carbonic acid. The carbonic acid partially dissociated
into H+ ions and its conjugate base (bicarbonate ions). Carbonic anhydrase
catalyzes the formation of carbonic acid (in tissues) and vice versa (in the lungs).
In the lungs, the carbon dioxide is expelled. </span>
Answer:
The color of the surfaces because an object with a black surface will absorb and reradiate energy faster and at a higher concentration than the same object with a lighter colored surface.
Hey there!
It can be assumed that the two black guinea pigs have one dominant gene, black fur, and one recessive gene, white fur. Using BB, Bb, and bb, when you look at this on a Punnett square, one out of the four boxes will be BB, which will end up with black fur, two boxes will be Bb, which will also end up with black fur, and one box will be bb, which will end up with white fur. If the parent guinea pigs were BB, all of the offspring would be black. If they were bb, they would be white instead of black.
Hope this helped you out! :-)
Answer:
C. Molecules such as cyclins are in high concentration in the cytoplasm of a dividing cell and will signal the fused cells nucleus to undergo mitosis
Explanation:
Various stages of the cell cycle are under tight regulation. Specific proteins such as cyclins and cyclin-dependent protein kinases determine if the cell would progress from one stage of the cell cycle to the next. When a cell is in the metaphase, the cyclins specific for mitosis are present in a higher amount in the cell. These cyclins bind to the specific CDKs and activate them.
The activated CDKs then phosphorylate proteins that make the cell to move through various stages of mitosis. Therefore, fusing a G1 cell with a cell in metaphase of mitosis would trigger mitosis in the G1 cell due to the presence of mitosis specific cyclins in the second cell.