If genotypically one of the parents is homozygous dominant and another one is heterozygous for plant height then phenotypically all their progeny will be tall.

Let us suppose, 'T' represents dominant allele and 't' represents recessive allele. Then the genotype of one parent who is homozygous dominant will be TT and genotype of another parent who is heterozygous will be Tt.

The cross is depicted in the attachment.

Here it may also be noted that genotypically two of the progeny will be homozygous dominant while two of the progeny will be heterozygous but phenotypically all the progeny will be 'tall'.

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3 years ago

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If Huntington's disease is due to a dominant trait, shouldn't three-fourths of the population have Huntington's while one-fourth

4vir4ik [10]

This would be probably true if the assumption that all possible genotypic variations would be equally distributed (so we would have 25% HH, 25% hh and 2x 25 Hh). If this distribution would be true and Huntingtons disease really was a single gene dominant trait diesase, then yes, we could expect such a distribution in the population.

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3 years ago