Answer:
maximum height on moon is 6 times more than the maximum height on Earth
Explanation:
Let the Astronaut has its maximum speed by which he can jump is "v"
now for the maximum height that it can jump is given as
now from above equation we will have
now we have
now if Astronaut jump on the surface of moon with same speed
then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth
so at surface of moon we have
now we have
so maximum height on moon is 6 times more than the maximum height on Earth
Answer:
88.8 m/s= Speed of wave propagation in the required mode.(3 loops)
Explanation:
When there are 3 loops.
the total length = L = 3 λ /2
⇒ λ = 2 L / 3 = 2 ( 1.11 ) / 3 = 0.74 m
Velocity = v = f λ = (120)(0.74) = 88.8 m/s
To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.
<h3>How to identify the median?</h3>
In a box plot, this value is represented by a vertical line located in the middle of the graph.
<h3>How to identify the maximum and the minimum?</h3>
The maximum is the value located on the farthest right, while the minimum is located on the farthest left.
<h3>How to identify the quartiles?</h3>
Divide the graph into 4 and analyze how much each quartile represents.
Learn more about graphs in: brainly.com/question/16608196
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<span>Her center of mass will rise 3.7 meters.
First, let's calculate how long it takes to reach the peak. Just divide by the local gravitational acceleration, so
8.5 m / 9.8 m/s^2 = 0.867346939 s
And the distance a object under constant acceleration travels is
d = 0.5 A T^2
Substituting known values, gives
d = 0.5 9.8 m/s^2 (0.867346939 s)^2
d = 4.9 m/s^2 * 0.752290712 s^2
d = 3.68622449 m
Rounded to 2 significant figures gives 3.7 meters.
Note, that 3.7 meters is how much higher her center of mass will rise after leaving the trampoline. It does not specify how far above the trampoline the lowest part of her body will reach. For instance, she could be in an upright position upon leaving the trampoline with her feet about 1 meter below her center of mass. And during the accent, she could tuck, roll, or otherwise change her orientation so she's horizontal at her peak altitude and the lowest part of her body being a decimeter or so below her center of mass. So it would look like she jumped almost a meter higher than 3.7 meters.</span>
