It mainly depends on the season of the year
<h2>
Answer: as mass increases, the wave nature of matter is less easy to observe.</h2>
At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>
In this sense, the de Broglie wavelength 
is given by the following formula:
(1)
Where:
is the Planck constant
is the momentum of the atom, which is given by:
(2)
Where:
is the mass
is the velocity
Substituting (2) in (1):
![\lambda=\frac{h}{m.v}[\tex] (3)As we can see, if we increase the mass, the wavelength decreases (because [tex]\lambda](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bh%7D%7Bm.v%7D%5B%5Ctex%5D%20%20%3Cstrong%3E%20%283%29%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3EAs%20we%20can%20see%2C%20%3Cstrong%3Eif%20we%20increase%20the%20mass%2C%20the%20wavelength%20decreases%20%3C%2Fstrong%3E%28because%20%5Btex%5D%5Clambda)
is inversely proportional to ).
Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.
The other options are incorrect because:
a) as increases decreases and the particle nature matter becomes more evident
b) as decreases increases and the wave nature matter becomes more evident
c) There is also a relation between the wavelength and the energy 
:
So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe
Answer:
-20.0 m/s and 30.0 m/s
Explanation:
Momentum is conserved:
m (30.0) + m (-20.0) = m v₁ + m v₂
30.0 − 20.0 = v₁ + v₂
10.0 = v₁ + v₂
Since the collision is perfectly elastic, energy is also conserved. Since there's no rotational energy or work done by friction, the initial kinetic energy equals the final kinetic energy.
½ m (30.0)² + ½ m (-20.0)² = ½ mv₁² + ½ mv₂²
(30.0)² + (-20.0)² = v₁² + v₂²
1300 = v₁² + v₂²
We now have two equations and two variables. Solve the system of equations using substitution:
1300 = v₁² + (10 − v₁)²
1300 = v₁² + 100 − 20v₁ + v₁²
0 = 2v₁² − 20v₁ − 1200
0 = v₁² − 10v₁ − 600
0 = (v₁ + 20) (v₁ − 30)
v₁ = -20, 30
If v₁ = -20, v₂ = 30.
If v₁ = 30, v₂ = -20.
So either way, the final velocities are -20.0 m/s and 30.0 m/s.
Pv/t = constant
when t is constant
p increases v must be increase
Answer:
Angular acceleration = -1.57 Rad/s^2
Number of revolutions = 800 revolutions
Explanation:
Mass = 1.15kg
diameter of the grinding wheel = 22.0cm
angular speed = 20 rev/s
1 Rev/s = 6.283 rad/s
20 Rev/s = 20 * 6.283 = 125.664 rad/s
Angular acceleration = Angular speed/ time taken for for the wheel rotation
Angular accleration = 125.664/80
Angular acceleration = -1.57 rad/s^2 (since the wheel is rotating counterclockwise)
number of revs = 0.5∝t²
number of revs = 0.5 * (1.57/2π) * 80²
number of revs = 800 revolutions
