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OLEGan [10]
3 years ago
5

What is the solar process that results in the production of energy? A. nuclear fission B. nuclear fusion C. convection D. radiat

ion
Physics
2 answers:
exis [7]3 years ago
6 0

Answer:

B. Nuclear fusion

Explanation:

- Nuclear fusion is the process in which small nuclei (such as hydrogen) fuse together into heavier nuclei (for example, helium). In such process, the final mass of the product is less than the sum of the masses of the initial nuclei, therefore the mass which 'disappeared' has been converted into energy, according to Einstein's equation:

E=\Delta m c^2

where

\Delta m is the difference of mass between products and reactants

c is the speed of light

Because c is a very large value (c=3.0\cdot 10^8 m/s), the amount of energy released during nuclear fusion is very huge, even for very small masses. This is the process that occurs inside the core of a star, and because of that, stars are able to produce very huge amounts of energy.

kirill115 [55]3 years ago
5 0
Nuclear Fusion is hopefully the answer to your question.
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The skater's final angular speed is equal to 12 rad/s.

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1 year ago
Which of these stars has the hottest core?A)a blue main-sequnce star. B)a red supergiant. C)a red main-sequence star.
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The question you have asked is a
3 0
3 years ago
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What objects do balanced forces act on?
leva [86]

Answer: Stationary or constant velocity

Explanation:

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3 years ago
Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.00×104 Pa . Assum
cestrela7 [59]

Answer:

T_{2}=278.80 K

Explanation:

Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.

(\frac{V_{1}}{V_{2}})^{\gamma -1} = \frac{T_{2}}{T_{1}}.

Now, let's use the ideal gas equation to the initial and the final state:

\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}

Let's recall that the term nR is a constant. That is why we can match these equations.  

We can find a relation between the volumes of the initial and the final state.

\frac{V_{1}}{V_{2}}=\frac{T_{1}p_{2}}{T_{2}p_{1}}

Combining this equation with the first equation we have:

(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}

(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}

Now, we just need to solve this equation for T₂.

T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}

Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.

Here,

p_{2}=8.00\cdot 10^{4} Pa \\p_{1}=1.01\cdot 10^{5} Pa\\ T_{1}=298 K\\ \gamma=1.40

Finally, T2 will be:

T_{2}=278.80 K

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