Scopes, who has substituted for the regular biology teacher was charged on May the 5th, 1925 with teaching evolution from a chapter in George William Hunters textbook. Civic Biology: Presented in problems which described the theory of evolution... Hope this helps!
Answer:
RE of Hydrogen = 6.47 x RE of Krypton
Explanation:
Actually the correct formula for comparing rate of effusion (RE) of two gases is:
RE of Gas A
------------------- = √ ( Molar mass of B / Molar mass of A)
RE of Gas B
You can designate which of the two gases you have (hydrogen and krypton) will be your gas A and gas B. So for this particular problem, let us make hydrogen as gas A and Krypton as gas B. So the equation becomes:
RE of Hydrogen
------------------------- = √ (Molar mass of Krypton / Molar mass of Hydrogen)
RE of Krypton
Get the molar masses of Hydrogen and Krypton in the periodi table:
RE of Hydrogen
------------------------- = √ (83.798 g/mol / 2 g/mol)
RE of Krypton
RE of Hydrogen
------------------------- = 6.47 ====> this can also be written as:
RE of Krypton
RE of Hydrogen = 6.47 x RE of Krypton
It means that the rate of effusion of Hydrogen gas will be 6.47 faster than the rate of effusion of Krypton gas. With the type of question you have, it doesn't matter which gases goes on your numerator and denominator. What's important is that you show the rate of effusion of a gas with respect to the other. But if that's concerns you the most, then take the gas which was stated first as your gas A and the latter as your gas B unless the problem tells you which one will be on top and which is in the bottom.
Since
Force (weight) = mass x acceleration (gravity)
To determine acceleration, the formula will be:
Acceleration = Force / mass
Given are:
F = 10 N
M = 2kg
A = ?
Solution:
1. A = F/M
2. A = 10 kg*m/s2 / 2kg
3. A = 5 m/s2
Answer:
2465 J/g
Explanation:
The amount of energy required to boil a sample of water already at boiling point is given by
where
m is the mass of the water sample
is the specific latent heat of vaporization of water
In this problem, we know
Solving the equation for , we find
