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OLEGan [10]
3 years ago
5

What is the solar process that results in the production of energy? A. nuclear fission B. nuclear fusion C. convection D. radiat

ion
Physics
2 answers:
exis [7]3 years ago
6 0

Answer:

B. Nuclear fusion

Explanation:

- Nuclear fusion is the process in which small nuclei (such as hydrogen) fuse together into heavier nuclei (for example, helium). In such process, the final mass of the product is less than the sum of the masses of the initial nuclei, therefore the mass which 'disappeared' has been converted into energy, according to Einstein's equation:

E=\Delta m c^2

where

\Delta m is the difference of mass between products and reactants

c is the speed of light

Because c is a very large value (c=3.0\cdot 10^8 m/s), the amount of energy released during nuclear fusion is very huge, even for very small masses. This is the process that occurs inside the core of a star, and because of that, stars are able to produce very huge amounts of energy.

kirill115 [55]3 years ago
5 0
Nuclear Fusion is hopefully the answer to your question.
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I will Mark Brainliest 1. ) Allena and Charissa were discussing whether Cl2 is an element or a compound. Allena said that it is
WITCHER [35]
The answer to question one is A.
The answer to question two is A.
The answer to question three is D.

7 0
3 years ago
An electric dipole is formed from ± 5.0 nC point charges spaced 3.0 mm apart. The dipole is centered at the origin, oriented alo
Ymorist [56]

Answer:

The electric field strength at point (x,y) = ( 20 mm ,0cm) is =<u>16321.0769 N/C</u>

The electric field strength at point (x,y) = (0cm, 20 mm) is =<u>35321.58999 N/C</u>

Explanation:

Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?

Answer:

The electric field at any given point of the dipole is given as:

E= (KP) ÷ (r^2 + a^2)^3/2

Where:

K = 9x10^9 Nm^2/c^2 (coloumb constant)

P = (0.003) (5x10^-9c) which is the movement of the dipole

(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.

r= the point, in the question above is 20mm = 0.02m

Now, the electric field, E can be calculated by putting the values in the formula above:

E = (KP) ÷ (r^2 + a^2)^3/2

= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2

= 0.135 ÷ (8.271513x10^-6)

=<u>16321.0769 N/C</u>

 Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?

Answer:

Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2

E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2

= 0.0054 ÷  0.000000152881

=<u>35321.58999 N/C</u>

8 0
2 years ago
Calculate the force of attraction between
vagabundo [1.1K]

Answer:

So the force of attraction between the two objects is 3.3365*10^-6

Explanation:

m1=10kg

m2=50kg

d=10cm=0.1m

G=6.673*10^-11Nm^2kg^2

We have to find the force of attraction between them

F=Gm1m2/d^2

F=6.673*10^-11*10*50/0.1^2

F=3.3365*10^-8/0.01

F=3.3365*10^-6

4 0
3 years ago
Which line represents an object that is in motion where the acceleration is zero and the velocity is to the north?
Alex787 [66]

Answer:

what do the lines look like

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3 years ago
An spring has a period of 4 seconds. What is its frequency?
trasher [3.6K]

Answer:

2Hz

Explanation:

Hope this helps

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3 years ago
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