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Anna11 [10]
3 years ago
12

All of the following are examples of ways to improve energy efficiency of heating systems, except _______.

Physics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

D. Opening the front door in winter to filter and clean warm ai

Explanation:

All of the following are examples of ways to improve energy efficiency of heating systems, except _______.

A. Closing off rooms that aren’t in use.

B. Frequently cleaning the furnace filter.

C. Fixing cracks in the walls and floor.

D. Opening the front door in winter to filter and clean warm air

for an heating systems it is better to keep the front door shut so that all the heat energy does not escape outside.

when heat energy is within a closed system ,it can still be utilized to keep the inhabitants warm otherwise there will be an exchange with the cold from winter fall outside the air, and the heating system's efficiency will be reduced

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If an arrow is shot upward on the moon with a velocity of 58 m/s, its height (in meters) after t seconds is given by H = 58t − 0
Alex73 [517]

Answer:

a) v = 54.7m/s

b) v = (58 - 1.66a) m/s

c) t = 69.9 s

d) v = -58.0 m/s

Explanation:

Given;

The height equation of the arrow;

H = 58t - 0.83t^2

(a) Find the velocity of the arrow after two seconds. m/s;

The velocity of the arrow v can be given as dH/dt, the change in height per unit time.

v = dH/dt = 58 - 2(0.83t) ......1

At t = 2 seconds

v = dH/dt = 58 - 2(0.83×2)

v = 54.7m/s

(b) Find the velocity of the arrow when t = a. m/s

Substituting t = a into equation 1

v = 58 - 2(0.83×a)

v = (58 - 1.66a) m/s

(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s

the time when H = 0

Substituting H = 0, we have;

H = 58t - 0.83t^2 = 0

0.83t^2 = 58t

0.83t = 58

t = 58/0.83

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v = dH/dt = 58 - 2(0.83t)

Substituting t = 69.9s

v = 58 - 2(0.83×69.9)

v = -58.0 m/s

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3 years ago
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