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Sav [38]
3 years ago
7

What is the speed of a bobsled whose distance-time graph indicates that it traveled 122m in 27s?

Physics
1 answer:
Stolb23 [73]3 years ago
7 0
Speed = distance/time
speed= 122÷27=4.52m/s (3sf)
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An object is in free fall. After 10 seconds calculate the distance fallen?
maxonik [38]

Answer:

D.490.5\ m

Explanation:

We\ are\ given\ that,\\Acceleration\ due\ to\ gravity\ (On\ Earth)=9.81\ m/s^2\\Initial\ Velocity\ of\ the\ body=0\ m/s\\Time\ taken=10\ seconds\\Hence,\\From\ the\ Second\ Equation\ of\ Motion:\\S=ut+\frac{1}{2}at^2\\By\ reconstructing\ the\ equation:\\S=ut+ \frac{1}{2}gt^2\\Hence, here\\S=0*10+\frac{1}{2}*9.81*10^2\\S=\frac{1}{2}*981\\S=490.5\ m

6 0
3 years ago
Compare and contrast speed and velocity
Alex73 [517]
Where speed is distance/time, velocity is displacement/time. 

What this means is that velocity is the length covered in relation to the starting point. 
Speed is just the distance travelled no matter where you began. 

When going around a circular track, you might have a speed value. However, since you get back to the same location at every lap, you have 0 velocity. 

Hope I helped :)
8 0
4 years ago
This type of bike tire is thinner, lighter, more expensive, and punctures easily.
maria [59]
There are 3, Tubular, Clincher, and tubeless.
4 0
3 years ago
If an electrical component with a resistance of 53 Q is connected to a 128-V source, how much current flows through the componen
natta225 [31]

Answer:

the current that flows through the component is 2.42 A

Explanation:

Given;

resistance of the electrical component, r = 53 Ω

the voltage of the source, V = 128 V

The current that flows through the component is calculated using Ohm's Law as demonstrated below;

V = IR\\\\I = \frac{V}{R} = \frac{128 \ V}{53 \ ohms} = 2.42 \ A

Therefore, the current that flows through the component is 2.42 A

8 0
3 years ago
at a particular instant a hot air balloon is 100m in the air and decending at a constant speed of 2m/s at this exact instant a g
labwork [276]
<h2>She will find the ball at a horizontal distance of 86.4 m from landed location</h2>

Explanation:

Consider the vertical motion of ball

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 2 m/s

        Acceleration, a = 9.81 m/s²  

        Displacement, s = 100 m      

     Substituting

                      s = ut + 0.5 at²

                      100 = 2 x t + 0.5 x 9.81 xt²

                      4.905t²  + 2t - 100 = 0

                     t = 4.32 s    or   t = -4.72 s

                    After 4.32 seconds the ball reaches ground.

Now we need to find horizontal distance traveled by ball in 4.32 seconds.

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 20 m/s

        Acceleration, a = 0 m/s²  

        Time, t = 4.32 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 20 x 4.32 + 0.5 x 0 x 4.32²

                      s = 86.4 m

She will find the ball at a horizontal distance of 86.4 m from landed location

5 0
4 years ago
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