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Sav [38]
3 years ago
7

What is the speed of a bobsled whose distance-time graph indicates that it traveled 122m in 27s?

Physics
1 answer:
Stolb23 [73]3 years ago
7 0
Speed = distance/time
speed= 122÷27=4.52m/s (3sf)
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A ball is launched from a slingshot. As the ball travels along its trajectory, what force(s) are acting on it? Select all that a
ZanzabumX [31]

Force of air and gravitational force are acting on the ball when launched from the slingshot.

When a ball is launched from a slingshot, during its travel force of air as well as gravitational force are acting on the ball because there is air which moves opposite to the motion of a ball whereas the force of gravity attracts the ball downward.

The force of air slows down the motion of the ball while on the other hand, the force of gravity brings the ball to the ground due to attraction. If these two forces are not present then the ball continues its motion forever so we can conclude that force of air and force of gravity are acting on the ball when launched from the slingshot.

Learn more: brainly.com/question/25533186

4 0
3 years ago
Cual es la notación cientifica de 5 983 000 000 000 000 000 000 000
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3 0
4 years ago
hi:) is displacement time graph the same as distance time graph? if nope, then what’s the difference?
Illusion [34]
A displacement time graph is able to show if an object is going backwards or forwards for example usually a line with a negative gradient means going backwards (or back to the start) This CAN’T be shown on a distance time graph

A distance time graph shows how far an object has traveled in a given time
So for example...

Distance is plotted on the Y-axis
Time is plotted on the X-axis

So not they are not the same, hope this helped :)
4 0
3 years ago
Read 2 more answers
The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to
Karolina [17]

Answer:

<h2>t = 2.35s</h2>

Explanation:

Using one of the equation of motion expressed as v = u+at where;

v is the final velocity = 2.0m/s

u is the initial velocity = 25m/s

a is the acceleration = -a (since the acceleration is negative)

t is the time taken

Substituting the given parameters into the formula above;

2.0 = 25-9.81t

subtract 25 from both sides

2.0 - 25 = 25-9.81t - 25

-23 = -9.81t

Divide both sides by -9.81

-23/-9.81 = -9.81t/-9.81

t = 23.0/9.81

t = 2.35s

<em>Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s</em>

4 0
3 years ago
A cart is pushed to the right with a force of 15 N while being pulled to the left with a force of 20 N. The net force on the car
9966 [12]

The net force of the cart when it is pushed to the right with a force of 15N.

<u>Explanation:</u>

To find the force of net, which is calculated by the  formula.

The Net Force= Addition of the force applied on the respective  direction.

The Net Force here is given by

The Net Force = 15-20 (A force towards the right and a force towards left, two opposite so subtraction).

Hence

Thus the Net Force = -5(The force towards left, so it gets a  negative value).

5 0
4 years ago
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