Adam<span> applies and input force to the pulley as he pulls down to </span>lift the object<span>. As he does this, </span>Adam<span>wonders about how the pulley is </span>helping<span> him
</span>
Answer:
f=-1380N
Explanation:
A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds
.the concluding part to the question should be
What is the impact force (impulse) on the board?
solution
from the Newton's second law of motion which states that
the rate of change in momentum is directly proportional to the force applied
f=m(v-u)/t
f=0.3(0-23.3)/0.005
f=-1380N
f=force impact
m=mass of the karates master's hand
t=time for the impact
v=0m/s final velocity
u=initial velocity
Answer: Option (c) is the correct answer.
Explanation:
When a penny is dropped from a height of 20 meters then it will achieve an acceleration.
As acceleration is the rate of change in velocity of an object with respect to time. Therefore, the velocity does not remain constant.
Whereas mass of the penny will remain the same as it will not get affected when it falls. Also, there will be no change in direction of the penny as it is falling only in one direction.
The acceleration of penny is due to the force of gravity.
Thus, we can conclude that the force of gravity causes it to accelerate.
Answer:
it's the second one;
if the frequency increases, wavelength decreases
Explanation:
we know, v=f×lamda(wave length)
so for constant velocity Frequency f is inversely proportional to lamda
i.e.
fα 1/lamda
so as the f increases lamda decreases and vise versa
The answer:
<span>When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes
</span>A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the <span>Tension in upper rope
</span> and
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope
When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²
T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
and
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope