All categories

2 years ago

How many calories are equal to one BTU? (One calorie = 4.186 J, one BTU = 1 054 J.)

Physics

2 answers:

natima [27]2 years ago

5 0

Answer:

Explanation:

Given

1 calorie is equals to 4.186 J

and 1 BTU equals to 1054 J

using unitary method

$1\ calorie \equiv 4.186 J$

$1\ calorie \equiv 4.186 \times 1 J$

and $1\ J \equiv \frac{1}{1054} BTU$

thus $1\ calorie \equiv 4.186 \times \frac{1}{1054} BTU$

$1\ calorie\ \equiv 0.00397 BTU$

$1\ calorie\ \equiv 397\time 10^{-5} BTU$

or $BTU=251.88\approx 252 cal$

expeople1 [14]2 years ago

4 0

Answer:

option (c)

Explanation:

According to the question

1 BTU = 1054 J

4.186 J = 1 cal

So, 1 J = 1/4.186 cal

So, 1054 J = 1054 / 4.186 cal

= 251.8 cal

By rounding off, it is 252 cal

So, 1 BTU = 252 cal

You might be interested in

When a negatively charged object moves in the opposite direction of an electric force field, the potential energy of the object

Simora [160]

The best and most correct answer among the choices provided by the question is decreases <span>.

</span>The potential energy of the object <span>decreases.</span>

Hope my answer would be a great help for you.
If you have more questions feel free to ask here at Brainly.

3 0

2 years ago

Read 2 more answers

What was Sylvester James Gates biggest discovery

Dahasolnce [82]

Sylvester James Gates' biggest discovery was the string theory which involves computer coding. I hope this answer helped.

8 0

3 years ago

Read 2 more answers

A ball of a mass 0.3 kg is released from rest at a height of 8 m. How fast is it going when it hits the ground? Acceleration due

Vaselesa [24]

In order to solve this problem, there are two equations that you need to know to solve this problem and pretty much all of kinematics. The first is that d=0.5at^2 (d=vertical distance, a=acceleration due to gravity and t=time). The second is vf-vi=at (vf=final velocity, vi=initial velocity, a=acceleration due to gravity, t=time). So to find the time that the ball traveled, isolate the t-variable from the d=0.5at^2. Isolate the t and the equation now becomes $\sqrt{(2d)/a}$ . Solving the equation where d=8 and a=9.8 makes the time $\sqrt{(2*8)/9.8}$ =1.355 seconds. With the second equation, the vi=0 m/s, the vf is unknown, a=9.8 m/s^2 and t=1.355 sec. Substitute all these values into the equation vf-vi=at, this makes it vf-0=9.8(1.355). This means that the vf=13.28 m/s.

8 0

2 years ago

Read 2 more answers

What happens as photons of visible light are absorbed by dye molecules?

rjkz [21]

Certain electrons in the dye molecule move to a higher energy level, with the difference in energy between the lower and higher energy levels being the same as the energy of the absorbed photons.

3 0

2 years ago

A thin, uniform metal bar, 2.00 m long and weighing 90.0 N, is hanging vertically from the ceiling by a frictionless pivot. Sudd

matrenka [14]

Answer:

(a) The "angular speed" is 5.88 rad/s.

Explanation:

Given values,

The length of the bar is L = 2m

The weight of the bar is w = 90 N

The metal bar is hanging vertically from the ceiling by a frictionless pivot

The mass of the ball is m = 3kg

The distance between the ceiling and the ball is d = 1.5m

$\text { The "initial speed of the ball" is } V_{i}=10 \mathrm{m} / \mathrm{s}$

$\text { The "final speed of the ball" is } V_{f}=6 \mathrm{m} / \mathrm{s}$

(a) Calculating the angular speed:

$W_{\mathrm{f}}=\left(3 \mathrm{mg} \mathrm{d} \frac{V_{i}+V_{f}}{w l^{2}}\right)$

$W_{f}=\left(3 \times 3 \times 9.8 \times 1.5 \times \frac{10+6}{90 \times 2^{2}}\right)$

$W_{f}=\frac{2116.8}{360}$

$\mathrm{W}_{\mathrm{f}}=5.88 \mathrm{rad} / \mathrm{s}$

The angular speed is 5.88 rad/s.

(b) The "angular momentum" is conserved because the torque is not exerted by "the pivot" on the system about the "axis of rotation" but the "linear momentum" is not conserved because "the pivot" exerts a "vertical" and a "horizontal force" on the system during the collision.

8 0

3 years ago