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PLEASE POST YOUR QUESTIONS IN ENGLISH, ANYONE CAN REPORT YOU FOR DOING THIS BE CAREFULL
<span>In their mechanism of action, a difference between lipid-soluble and water-soluble hormones is that </span>lipid-soluble hormones diffuse into the cell's plasma membrane to access protein receptors, while water-soluble hormones bind to protein receptors on the plasma membrane without diffusion.
Examples of lipid-soluble hormones are steroids. Examples of water-soluble hormones are polypeptides.
Answer:
4 sig figs
Explanation:
<h3>Rule when dividing or multiplying:</h3>
After normally solving the expression cut round the decimal to the least accurate of the two.
54.50/50.407 = 1.08119904
Since 54.50 is the least accurate we will round to the hundredths place.
1.081 is final answer
so there are 4 sig figs.
Answer:
D. C + 2H₂ + ¹/₂O₂ → CH₃OH
Explanation:
The standard enthalpy of formation -ΔHf- is defined as the enthalpy change for the formation of 1 mol of a compound from its component elements.
Component elements are any element in its standard state.
For CH₃OH(l) at 25°C and 1 atm of pressure, the component elements are C(s), H₂(g) and O₂(g)
Thus, the equation that represent the standard enthalpy of formation of CH₃OH(l) is:
D. C + 2H₂ + ¹/₂O₂ → CH₃OH
I hope it helps!
