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photoshop1234 [79]
3 years ago
5

An analysis of an ionic compound is found to contain 92 grams of sodium (Na) and 32 grams of oxygen (O). Determine the empirical

formula of the compound
A. Na2O
B. NaO
C. NaO2
D. Na2O2

Chemistry
2 answers:
Darina [25.2K]3 years ago
6 0
The answer would be c nao2
Dmitry_Shevchenko [17]3 years ago
3 0

Answer: option A. Na2O

Explanation:Please see attachment for explanation

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Manganese nodules are considered a valuable resource from the ocean floor because they are abundant and contain not only mangane
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Answer: iron (oxides of iron)

Explanation: manganese nodules usually contain layers of iron and manganese oxides in a concentric arrangement and are called polymetallic nodules.

4 0
3 years ago
CH3CH2OH + 302 → 2C02 + 3H2O
Colt1911 [192]

Answer:

Oxygen Gas

Explanation:

The balanced equation shows us the reactant ratio of the reaction.

This means that for every one mole of CH3CH2OH, we need 3 moles of O2 to react with it. Because we need more O2, (3x as much) than ethanol and we have the same given amount (1 mole of each), the oxygen will be the limiting reagent. (1 mole of oxygen would only require 1/3 moles of ethanol to react).

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7 0
2 years ago
QUESTION TWO
igomit [66]

Answer: The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century. It involves careful observation, applying rigorous skepticism about what is observed, given that cognitive assumptions can distort how one interprets the observation.

Explanation:

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3 0
3 years ago
How does wavelength differ in high and low frequency waves?
Taya2010 [7]
Waves with higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths
4 0
3 years ago
Read 2 more answers
How many grams of CH4 will be in a 500ml contain at STP?
ArbitrLikvidat [17]

Answer:

Mass = 0.32 g

Explanation:

Given data:

Mass of CH₄ = ?

Volume of CH₄ = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Temperature = 273 K

Pressure = 1 atm

Solution:

Volume of CH₄:

500 mL (500 mL× 1L/1000 mL= 0.5 L)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm× 0.5 L = n×0.0821 atm.L/ mol.K  × 273 K

0.5 atm.L = n×22.4 atm.L/ mol

n = 0.5 atm.L / 22.4 atm.L/ mol

n = 0.02 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.02 mol × 16 g/mol

Mass = 0.32 g

7 0
3 years ago
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