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Norma-Jean [14]
2 years ago
13

I FORGOT HOW TO SHOW THE SLIDE BUT -Yosef is so intrigued by what he sees in his microscope that he walks to a nearby pond and c

ollects a sample of pond water to learn more about paramecium. He uses a single drop of the pond water to create a wet mount slide, which allows him to see living paramecia moving around in the water, unlike the processed and dyed paramecia in the prepared slide How do the structures observed under magnification help the organism carry out basic functions of life? - PLS HELP IT WAS DUE YESTERDAY
Chemistry
1 answer:
myrzilka [38]2 years ago
8 0

The structure of paramecium observed under magnification that helps the organism carry out basic functions of life is ; CILIA

The paramecium has a oral surface and a dorsal body surface that is covered with pellicles ( elastic firm membrane ) that supports the cell membrane of the paramecium.  while The whole body of a paramecium is covered with Cilia ( hair like filaments ) that supports the propelling movement of the paramecium and the movement of food particles into the mouth of the paramecium.

The basic function of a paramecium are ; (i) movement and ( ii ) feeding. the CILIA is the structure that helps the organism to carry out these functions.

Hence we can conclude that structure of paramecium observed under magnification that helps the organism carry out basic functions of life is CILIA .

Learn more : brainly.com/question/21649679

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})
  2. Multiply:                                                                                                             \displaystyle 18.9306 \ g \ F_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

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3 years ago
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