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2 years ago

How could you safely determine if a base is stronger than an acid?

1 answer:

4 0

Combine the two solutions. If the resulting salt is basic, you know the base was stronger. If you end up with an acidic salt, the acid was stronger.

You might be interested in

Which atoms make up a molecule of sodium bicarbonate.

Ratling [72]

Answer:

Its chemical formula is NaHCO3. Its formula consists of one sodium (Na) atom, one hydrogen (H) atom, one carbon (C) atom and three oxygen (O) atoms.

Explanation:

Hope this helps

8 0

1 year ago

What is the pressure in millimeters of mercury of 0.0130 molmol of helium gas with a volume of 210. mLmL at 55 ∘C∘C? (Hint: You

juin [17]

Answer : The pressure of the helium gas is, 1269.2 mmHg

Explanation :

To calculate the pressure of the gas we are using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $He$ gas = ?

V = Volume of $He$ gas = 210. mL = 0.210 L (1 L = 1000 mL)

n = number of moles $He$ = 0.0130 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $He$ gas = $55^oC=273+55=328K$

Putting values in above equation, we get:

$P\times 0.210L=0.0130mole\times (0.0821L.atm/mol.K)\times 328K$

$P=1.67atm=1269.2mmHg$

Conversion used : (1 atm = 760 mmHg)

Thus, the pressure of the helium gas is, 1269.2 mmHg

4 0

2 years ago

What is the volume of an object that has a mass of 3.5 grams and has a density of 2.50 g/mL? Include units and proper sig figs l

jolli1 [7]

1.4mL

Explanation:

Given parameters:

Mass of object = 3.5g

density = 2.5g/mL

Unknown:

Volume of the object = ?

Solution:

Density is the mass per unit volume of a body. It is an intensive property that is the same for the same substances.

Density = $\frac{mass}{volume}$

since the volume is unknown; we make it the subject of the formula;

Volume = $\frac{mass}{density}$

Volume = $\frac{3.5}{2.5}$

Volume of the object = 1.4mL

learn more:

Density brainly.com/question/4825250

#learnwithBrainly

8 0

2 years ago

Determina el grado de pureza de un marmol (CaCO3), si al descomponerse 125 g del mismo se desprenden 20 litros de dióxido de car

jarptica [38.1K]

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = 84.7g de CaCO₃

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100 =

7 0

2 years ago

Carbon monoxide (CO) is a poisonous gas because it binds very strongly to the oxygen carrier hemoglobin in blood. A concentratio

velikii [3]

Answer: The amount of CO that is occupied in the room is $1.98\times 10^3L$

Explanation:

We are given:

Concentration of CO = $8.00\times 10^2ppm=800pm$ by volume

This means that $800\mu L\text{ or }800\times 10^{-6}$ of CO is present in 1 L of blood

To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.99 m

b = breadth of cuboid = 18.97 m

h = height of cuboid = 11.89 m

$V=10.99\times 18.97\times 11.89=2478.83m^3$

Converting this into liters, by using conversion factor:

$1m^3=1000L$

So, $2478.83m^3=2.479\times 10^6L$

Applying unitary method:

In 1 L of blood, the amount of CO present is $800\times 10^{-6}$

So, in $2.479\times 10^6L$ of blood, the amount of CO present will be = $\frac{800\times 10^{-6}}{1}\times 2.479\times 10^{6}=1983.2L=1.98\times 10^3L$

Hence, the amount of CO that is occupied in the room is $1.98\times 10^3L$

8 0

2 years ago