Answer:
The answer is (e) : phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase then amylo-(1,4-1,6)-transglycosylase.
Explanation:
Phosphoglucomutase: Convert glucose-6-phosphate to glucose-1-phosphate.
UDP-glucose pyrophosphorylase: Form UDP-glucose from glucose-1-phosphate.
Glycogen synthase: Add the new glucose from UDP-glucose to the growing glycogen chain.
Amylo-(1,4-1,6)-transglycosylase: This is a branching enzyme, it initiates formation of branches evolving from the main chain.
Answer:
- One mole of oxygen was used in this reaction.
- Two moles of water were produced from this reaction.
Explanation:
In addition: -<em> </em><em>T</em><em>w</em><em>o</em><em> </em><em>m</em><em>o</em><em>l</em><em>e</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em> </em><em>w</em><em>e</em><em>r</em><em>e</em><em> </em><em>u</em><em>s</em><em>e</em><em>d</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
Answer : Option C) The kinetic energy decreases as potential energy increases.
Explanation : As the target is fired high on the wall, the change in the energy that is observed as the arrow moves towards the target is kinetic energy starts to decrease as the arrow reaches nearer towards the target and the potential energy is observed to increase. So, in short the energy transformation is from kinetic energy from a moving arrow to potential energy when the arrow hits the target.
The answer is C, a catalyst. This is due to the fact that catalysts are substances that can be used to speed up a reaction by lowering the activation energy required. However, the catalyst itself is not actually used up during the reaction.
