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timama [110]
4 years ago
5

A data set has values ranging from a low of 10 to a high of 50. The class width is to be 10. What's wrong with using the class l

imits 10-20, 21-31, 32-42, 43-53 for a frequency table with a class width of 10?
Mathematics
2 answers:
Airida [17]4 years ago
8 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

What was  wrong with using the class limits 10-20, 21-31, 32-42, 43-53 for a frequency table with a class width of 10 is that the <span>classes listed have a class width of 11.</span>
Ainat [17]4 years ago
7 0

Answer and Explanation :

Given : A data set has values ranging from a low of 10 to a high of 50. The class width is to be 10.

To find : What's wrong with using the class limits 10-20, 21-31, 32-42, 43-53 for a frequency table with a class width of 10?

Solution :

The frequency of a class is the number of data entries in the class.

Each class have a lower class limit and an upper class limit.

The class width of the frequency is defined as the distance between the  lower limits of consecutive classes.

Class limits 10-20, 21-31, 32-42, 43-53

Highest limit is 50 but data has 53.

According to question,

Last class limit should be 43-50 which has class width 7 not 10.

Class limit is also not continuous.

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3 years ago
You have botles of water how many can you buy with a 20$ and a bottle is 1.25​
igomit [66]

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16 bottles

Step-by-step explanation:

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4 years ago
Find the length x.<br> х<br> 14 cm<br> 70°
adoni [48]

Answer:

14.90cm [a]

Step-by-step explanation:

To find x, we will apply " sine rule"

that is, sinA/a=sinB/b

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so we input the values we have

1/x =0.94/14

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3 0
3 years ago
Find the area of a 2-inch-wide decorative border around a rectangular canvas painting, where L is the length and W is the width
lions [1.4K]

Answer:

  4L +4W +16 square inches

Step-by-step explanation:

The area of the border is the equivalent of that of a rectangle with a width equal to the width of the border, and a length equal to the length of the midline of the border. That length is the perimeter of the rectangle that is L+2 units long and W+2 units wide.

  border midline length = 2((L+2) +(W+2)) = 2L +2W +8

Then the border area is ...

  border area = (border width)(border length) = (2)(2L +2W +8)

  border area = 4L +4W +16 . . . square inches

_____

You can also figure this as the difference between the area of the rectangle with the border and the area of the rectangle inside the border:

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4 0
3 years ago
Zara has paper rectangles of different sizes every rectangle is 5 cm longer than it is wide is there a proportional relationship
ANEK [815]

Zara has paper rectangles. Length and width of any rectangle is directly proportional.

<u>SOLUTION: </u>

Given, Zara has paper rectangles of different sizes  

Every rectangle is 5 cm longer than it is wide  

We have to find that is there a proportional relationship between the length and width of these rectangles.

From the given information, length is 5 cm longer than width for any rectangle.

Then, length of rectangle = 5 + width of rectangle.

When we increase width of rectangle length also increases. From above equation.

Hence, length and width of any rectangle is directly proportional.

4 0
3 years ago
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