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aniked [119]
2 years ago
15

A manager (who happens to be a white Anglo) is responsible for hiring personnel in her department. She is accurate 95% of the ti

me in assessing the qualifications of white Anglo candidates (that is, 95% of the candidates who are qualified she assesses as qualified and 95% of the candidates who are unqualified she assesses as unqualified). She is accurate only 80% of the time for candidates of color. She hires candidates (they then become employees) that she assesses as qualified. In the pool of candidates, 60% of white Anglo candidates and 60% of candidates of color are qualified.(1) what proportion of white Agnlo hirees are qualified?(2) what proportion of the person of color who are hired are qualified?
Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

Answer:

(a) The proportion of qualified anglo candidates hired is 96.6%.

(b) The proportion of qualified persons of color candidates hired is 85.7%.

Step-by-step explanation:

For the anglo candidates, the manager will hire two groups:

Group 1: the ones that are qualified and she assess correctly

Group 2: the ones that are not qualified but she does not assess correctly

If we consider a group of 100 Anglo candidates, 60 are qualified. The probability that they are in the Group 1 is:

P(G_1)=P(qualified=yes)*P(assess=right) = 0.6*0.95=0.57

The probability of being in Group 2 is

P(G_2)=P(qualified=no)*P(assess=wrong) =0.4*0.05= 0.02\\

The proportion of qualified anglo candidates hired is equal to the probability of being in Group 1, over the sum of the probabilities of being in Group 1 and 2:

P(qualified=yes;hired=yes)=\frac{P(G_1)}{P(G_1)+P(G_2)} =\frac{0.57}{0.57+0.02}\\ \\P(qualified=yes;hired=yes)=\frac{0.57}{0.59}= 0.966

The proportion of qualified anglo candidates hired is 96.6%.

For the people of color is the same analysis, but the probabilities of assessment are different.

Group 1: the ones that are qualified and she assess correctly

Group 2: the ones that are not qualified but she does not assess correctly

If we consider a group of 100 non-Anglo candidates, 60 are qualified. The probability that they are in the Group 1 is:

P(G_1)=P(qualified=yes)*P(assess=right) = 0.6*0.8=0.48

The probability of being in Group 2 is

P(G_2)=P(qualified=no)*P(assess=wrong) =0.4*0.2= 0.08\\

The proportion of qualified anglo candidates hired is equal to the probability of being in Group 1, over the sum of the probabilities of being in Group 1 and 2:

P(qualified=yes;hired=yes)=\frac{P(G_1)}{P(G_1)+P(G_2)} =\frac{0.48}{0.48+0.08}\\ \\P(qualified=yes;hired=yes)=\frac{0.48}{0.56}= 0.857

The proportion of qualified persons of color candidates hired is 85.7%.

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Troyanec [42]

The data from a dot plot can be analyzed to find the five number summary, from which a box plot can be constructed

The correct option for the details of the box plot that represents the dot plot data is;

<em>Box plot </em><em>titled ACT Score with a minimum of </em><em>18</em><em>, quartile 1 of </em><em>21</em><em>, median of </em><em>22</em><em>, quartile 3 of </em><em>23</em><em>, and maximum of </em><em>25</em>

The process of deriving the five number summary of the box plot above is as follows;

Known:

The data from the dot plot can be expressed in increasing order for analysis of a box plot as follows;

18, 19, 19, 19, 21, 21, 21, 21, <u>22, 22</u>, 22,22, 23, 23, 23, 24, 24, 25

The number of data points in the statistics, n = 18

Unknown:

The five number summary

Method:

Finding the five number summary as follows;

The minimum value = 18

The maximum value = 25

  • The first quartile, inclusive of the median Q₁ = The middle number of the lower half {18, 19, 19, 19, 21, 21, 21, 21, <u>22}</u> = The (9 + 1)/2 th term

∴ Quartile 1 = Q₁ = 5th term = 21

  • The second quartile, Q₂ = The median (the middle number) = (22 + 22)/2 = 22 = Quartile 2

Quartile 2 = 22

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Quartile 3 = 23

Combining the above 5 number summary, the correct option for the box plot representing the dot plot data, is therefore;

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Learn more about box and whiskers, and dot plots here;

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7 0
2 years ago
An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6
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Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6  times.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......

where, n = number trials (samples) taken = 6 trials

            r = number of success = at least 4

           p = probability of success which in our question is probability of

                 rolling a “six", i.e; p = 0.20

<u><em>Let X = Number of sixes on a die</em></u>

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X \geq 4)

P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6)

=  \binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}

=  15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}

=  0.0154 + 0.00154 + 0.000064

=  0.01696

<em />

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0
3 years ago
The question is:
kifflom [539]
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so when you plug in the numbers its 12^2 + 5^2 =169
which means 144+24=169

square root 169 = 13

AB =13 cm



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3 years ago
Divide. Express your answer in simplest form. 8 divided by 2 4/9​
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Answer:

3 3/11

Step-by-step explanation:

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2 years ago
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The larger of two numbers is four times the smaller number, and their difference is 18. Find the two numbers.
podryga [215]

Answer:

x = 12 , y = 10

Step-by-step explanation:

Let x , y are two numbers.

x > y

1 ) Three times the greater is 18 times their

difference

3x = 18( x - y )

x = 6( x - y )

x = 6x - 6y

6y = 5x

y = 5x/6 ——-( 1 )

2 ) 4 times the smaller is 4 less than twice

the sum of the two

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y = x -2 ——( 2 )

From ( 1 ) and ( 2 ) ,

5x/6 = x -2

( 5x /6 ) - x = -2

( 5x - 6x ) /6 = -2

-x = -12

x = 12

Put x = 12 in equation ( 2 ) , we get

y = 12 - 2

y = 10

Therefore ,

x = 12 , y = 10

7 0
3 years ago
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