1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aniked [119]
2 years ago
15

A manager (who happens to be a white Anglo) is responsible for hiring personnel in her department. She is accurate 95% of the ti

me in assessing the qualifications of white Anglo candidates (that is, 95% of the candidates who are qualified she assesses as qualified and 95% of the candidates who are unqualified she assesses as unqualified). She is accurate only 80% of the time for candidates of color. She hires candidates (they then become employees) that she assesses as qualified. In the pool of candidates, 60% of white Anglo candidates and 60% of candidates of color are qualified.(1) what proportion of white Agnlo hirees are qualified?(2) what proportion of the person of color who are hired are qualified?
Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

Answer:

(a) The proportion of qualified anglo candidates hired is 96.6%.

(b) The proportion of qualified persons of color candidates hired is 85.7%.

Step-by-step explanation:

For the anglo candidates, the manager will hire two groups:

Group 1: the ones that are qualified and she assess correctly

Group 2: the ones that are not qualified but she does not assess correctly

If we consider a group of 100 Anglo candidates, 60 are qualified. The probability that they are in the Group 1 is:

P(G_1)=P(qualified=yes)*P(assess=right) = 0.6*0.95=0.57

The probability of being in Group 2 is

P(G_2)=P(qualified=no)*P(assess=wrong) =0.4*0.05= 0.02\\

The proportion of qualified anglo candidates hired is equal to the probability of being in Group 1, over the sum of the probabilities of being in Group 1 and 2:

P(qualified=yes;hired=yes)=\frac{P(G_1)}{P(G_1)+P(G_2)} =\frac{0.57}{0.57+0.02}\\ \\P(qualified=yes;hired=yes)=\frac{0.57}{0.59}= 0.966

The proportion of qualified anglo candidates hired is 96.6%.

For the people of color is the same analysis, but the probabilities of assessment are different.

Group 1: the ones that are qualified and she assess correctly

Group 2: the ones that are not qualified but she does not assess correctly

If we consider a group of 100 non-Anglo candidates, 60 are qualified. The probability that they are in the Group 1 is:

P(G_1)=P(qualified=yes)*P(assess=right) = 0.6*0.8=0.48

The probability of being in Group 2 is

P(G_2)=P(qualified=no)*P(assess=wrong) =0.4*0.2= 0.08\\

The proportion of qualified anglo candidates hired is equal to the probability of being in Group 1, over the sum of the probabilities of being in Group 1 and 2:

P(qualified=yes;hired=yes)=\frac{P(G_1)}{P(G_1)+P(G_2)} =\frac{0.48}{0.48+0.08}\\ \\P(qualified=yes;hired=yes)=\frac{0.48}{0.56}= 0.857

The proportion of qualified persons of color candidates hired is 85.7%.

You might be interested in
How do I solve for y:<br> x²y² = 12/z²
Vika [28.1K]

Answer:

Y=Srt(12xs^2/z^2)

Step-by-step explanation:

Firstly

We multiply both sides with 1/x^2

We get

Y^2=12/z^2*1/x^2

Y^2=12x^2/z^2

Next: introduce a srt root

We have

Y=srt(12x^2/z^2)

8 0
3 years ago
3/7 what is the quotient
Andre45 [30]

Answer:

0.42....and its a repeating decimal.

Step-by-step explanation:

4 0
3 years ago
Simplify.<br> Remove all perfect squares from inside the square root.<br> V450 = 1
JulsSmile [24]
22 because it can be it for right case of fire fire reacts to the flame
6 0
3 years ago
Hey can you please help me posted picture of question
mixer [17]
The nature of roots of a quadratic equation can be determined from its discriminant.

Discriminant = b² - 4ac

b = coefficient of x term = 2
a = coefficient of squared term = 2
c = constant = 4

So,

Discriminant = 4 - 4(2)(4) = -28

Since the discriminant is negative, the two roots of the given equation will be complex .

Therefore, the answer to this question is option B
7 0
2 years ago
Help me please!!! i cant do these
LuckyWell [14K]

Answer:

sec(B)=b. ab/bc

sin(B)=c. ac/ab

csc(B)=f. ab/ac

cot(B)=a. bc/ac

tan(B)=e. ac/bc

cos(B)=d. bc/ab

Step-by-step explanation:

<u><em>SOHCAHTOA</em></u>

<u><em>Sine=Opposite/Hypotenuse</em></u>

<u><em>Cosine=Adjacent/Hypotenuse</em></u>

<u><em>Tangent=Opposite/Adjacent</em></u>

<u><em>SHACHOCotAO</em></u>

<u><em>Secant=Hypotenuse/Adjacent</em></u>

<u><em>Cosecant=Hypotenuse/Opposite</em></u>

<u><em>Cotangent=Adjacent/Opposite</em></u>

<u><em /></u>

6 0
1 year ago
Other questions:
  • Find the equation of the line passing
    5·1 answer
  • Anybody...Help!!!!!!!!!!!
    10·1 answer
  • Two angels of triangle measure 12 and 40 what is the measure of the third angle of the triangle
    13·2 answers
  • Jack is selling wristbands and headbands to earn money for camp. He earns $2 for each wristband and $3 for each headband. He wan
    11·1 answer
  • A parallelogram has a base of 12 cm and a height of 8 cm. What is the area of the parallelogram?
    12·1 answer
  • If the common difference in an arithmetic sequence is 4, and the 20th term is 36, what is the first term
    9·1 answer
  • A bicyclist started riding at 8:00am. The diagram below shows the distance the bicyclist has traveled at different times. What w
    11·1 answer
  • Please help I was out this day and this assignment is late
    10·2 answers
  • Please helppppp it’s due soon and I’m already failing my class!!!
    10·1 answer
  • 13 POOINNTSSS PLEASE HELP ON 6-10 AND 13 TIMED TYSM IF U ANSWER
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!