If we have I= 7.5 A:
I think my solution might just help you answer the problem on your own:
You have the formulas correct, watch your signs and BRACKETS.
B = μ0/(2π) (Current) / (Perpendicular distance)
Since μ0=4π E -7 Tm/A, we have:
B1 = (4πE-7 Tm/A)(7.5 A)/[2π (0.030 m)] = 5E-5 T
B2 = (4πE-7 Tm/A)(-7.5 A)/[2π (0.150 m)] = -1E-1 T
So BA = B1 + B2 = ?
(It looks like you just left out the square brackets, hence multiplying Pi and 0.03 and 0.15 instead of dividing them.)
<span>For the point B, the two distances are -0.060 m and +0.060 m. Be careful with the signs. Unlike point A, the two components will have the same sign.</span>
Answer:
1. 
2. 
Explanation:
Given:
length of copper cable, 
diameter of copper cable, 
current through the copper wire, 
We have the resistivity of copper, 
<u>We know that the resistance of a wire is given as:</u>

where:
cross sectional area of the wire


1.
<u>Now from the Ohm's law:</u>



2.
<u>From the Joules law the thermal energy generated as an effect of electrical energy is mathematically given as:</u>
<u />
where:
time duration for which the current flows
(∵ we have 3600 seconds in 1 hour)

In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
= (5 * 10) Kg m/s
= 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
Answer:
A. 0N
Explanation:
assume you're pulling in the positive direction, then we have 5 + (-5) = netforce = 0N
Answer:
Tornadoes form in unusually violent thunderstorms when there is sufficient (1) instability and (2) wind shear present in the lower atmosphere. Instability refers to unusually warm and humid conditions in the lower atmosphere, and possibly cooler than usual conditions in the upper atmosphere.
Explanation:
please don't delete my answer brainly i beg you