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Maksim231197 [3]
3 years ago
15

A car, initially traveling at 15 meters per second

Physics
1 answer:
AnnZ [28]3 years ago
3 0
The magnitude of the acceleration of the car is given by:
a= \frac{v_f-v_i}{t}
where
v_i=15 m/s is the initial speed of the car
v_f=25 m/s is the final speed of the car
t=4.0 s is the time it takes for the car to change its speed

Substituting these data into the formula, we find the magnitude of the average acceleration of the car:
a= \frac{25 m/s-15 m/s}{4.0 s}=2.5 m/s^2

therefore, the correct answer is <span>(1) 2.5 m/s^2.</span>
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Sedimentary rocks are the only rocks that can potentially containa.fossils.c.fractures.b.minerals.d.faults. Please select the be
Elena-2011 [213]
Hello <span>Mr1guy24 </span>


Question: <span>Sedimentary rocks are the only rocks that can potentially contain?
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8 0
4 years ago
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A 20 kg mass is moving at 10 m/s and collides with a stationary 5 kg mass, transferring all its momentum in the collision, what
Fudgin [204]

Answer:

v = 40 [m/s].

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

P=m*v\\

where:

m = mass [kg]

v = velocity [m/s]

P =20*10\\P =200 [kg*m/s]

Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.

v = P/m\\v = 200/5\\v = 40 [m/s]

3 0
3 years ago
A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog
ra1l [238]

Answer:

25J

Explanation:

Given parameters:

Mass of the dog  = 10kg

Speed of the dog  = 5m/s

Unknown:

The minimum energy required to stop the dog  = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

 To find the kinetic energy;

        K.E  = \frac{1}{2} m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

      K.E  =  \frac{1}{2}  x 10 x 5  = 25J

8 0
3 years ago
what is the mass of vertical column of air that exerts pressure of 1 atm over a10m by 10m square surface
Oksana_A [137]

Answer:

m=1.01\times 10^6\ kg

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg

So, the required mass of the vertical column of air is 1.01\times 10^6\ kg.

4 0
3 years ago
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