A car, initially traveling at 15 meters per second
1 answer:
The magnitude of the acceleration of the car is given by:
where
is the initial speed of the car
is the final speed of the car
is the time it takes for the car to change its speed
Substituting these data into the formula, we find the magnitude of the average acceleration of the car:
therefore, the correct answer is <span>(1) 2.5 m/s^2.</span>
where
Substituting these data into the formula, we find the magnitude of the average acceleration of the car:
therefore, the correct answer is <span>(1) 2.5 m/s^2.</span>
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Answer:
Tension in the supporting cable is = 4,866 N ≅4.9 KN
Explanation:
First of all, we need to understand that tension is a force, so the motion law
F = Ma applies perfectly.
From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.
Parameters given:
Mass of load = 1650 kg
Acceleration of load = ?
The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.
Time taken = distance covered / velocity
= = 3.73 seconds
∴Acceleration = ( initial velocity - final velocity )/ time taken
Note: Final velocity is = 0 since the body came to a rest.
Acceleration = = 2.95m/
Force acting on the cable = mass of elevator × acceleration of elevator
= 1650 × 2.95 = 4869.5 kg ≅ 4.9 KN
