A platinum sphere with radius 1.21 cm is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on
1 answer:
Answer:
1.556 N , 0.989 N, 0.567 N
Explanation:
Radius of sphere, r = 1.21 cm = 0.0121 m
density of platinum , d = 2.14 x 10^4 kg/m^3
density of mercury, d' = 13.6 x 10^3 kg/m^3
Volume of sphere,
V = 7.42 x 10^-6 m^3
Weight of sphere = volume of sphere x density of platinum x gravity
W = V x d x g = 7.42 x 10^-6 x 2.14 x 10^4 x 9.8 = 1.556 N
Buoyant force, B = Volume x density of mercury x gravity
B = 7.42 x 10^-6 x 13.6 x 10^3 x 9.8 = 0.989 N
Apparent weight = True weight - Buoyant force
Apparent weight = 1.556 - 0.989 = 0.567 N
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