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3 years ago

A wave with high amplitude _____.

2 answers:

8 0

The answer you are looking for is: 
Can either have low or high frequency. 
If that is what you are asking. 
Hope that helps!! 
Have a wonderful day!!

Lapatulllka [165]3 years ago

3 0

Assuming that this is referring to the same list of options that was posted before with this question, a wave with a high amplitude can have either a high or low frequency.

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Which lists imaging techniques that use wave behaviors in order of resolution from the best resolution to the worst?

ElenaW [278]

C.CT scan, X-ray imaging, MRI

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3 years ago

a ball is thrown straight up with an initial speed 40m/s.a) how high does it go? b) what will be its velocity be in 7 secs?c) ho

Vinil7 [7]

By how much would its speed reading increase with each second of fall? ... Ex 3.24 For a freely falling object dropped from rest, what is its acceleration at the end of the 5th second ... Pb 3.3 A ball is thrown straight up with an initial speed of 30 m/s. How high does it go, and how long is it in the air (neglecting air resistance)?.

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4 years ago

A car goes from a speed of 10m/s to 30m/s over 4s. If the car has a mass of 1000kg, How strong is the force pushing the car forw

dusya [7]

Answer:

i think ww

Explanation:

i think we need to calculate net force which is:

net force=m.a

..nf=1000kg×30m/s

therefore net force will be the answer you get whwn you multiply those two

5 0

3 years ago

Two resistors connected in series have an equivalent resistance of 724.5 Ω, when they are connected in parallel, their equivalen

dybincka [34]

Answer:

544.65 ohm and 179.84 ohm

Explanation:

Hello

Let

Resistor 1 (R1) and Resistor 2 (R2)

in series $R_{eq} =R1+R2$

in parallel

$\frac{1}{R_{eqp} } =\frac{1}{R1} +\frac{1}{R2}\\\\R1=R_{eqs} -R2\\\\R1 =724.5-R2 (equation 1)\\ R_{eqp}}=\frac{R1*R2}{R1+R2}\\\\\ 135.2 = \frac{R1*R2}{R1+R2}(equation 2)\\\\\\\\replacing 1 in \ 2\\\\probema data$

$135.2=\frac{(724.5-R2)(R2)}{724.5-R2+R2} }\\135.2=\frac{(-R_{2} ^{2}+724.5R2) }{724.5}\\ 135.2*724.5=-R_{2} ^{2}+724.5R_{2}\\\\R_{2} ^{2} -724.5R_{2} +97952.4 =0\\R_{2} =\frac{724.5 \±\sqrt{(-724.5^{2})-4(1)(97952.4) } }{2(1)}\\R_{2} =\frac{724.5\±\sqrt{(133092.25) } }{2(1)}\\\\R_{2} =\frac{724.5+364.81810}{2} \\R_{2} =544.65 ohm\\\\R_{2} =\frac{724.5-364.81810}{2} =179.84 ohm$ \\\\

let R2=544.65 and replace in equation 1

R1=724.5-544.65

R1=179.85

so, the resistors are 544.65 ohm and 179.84 ohm

Have a great day

7 0

4 years ago

WHAT- HOW WAS THIS NOT ACADEMIC? IT WAS A QUESTION ABOUT WHY BLACK HOLES ARE INVISIBLE LOL.

LenKa [72]

Answer:

brainly getting too strict smh...

Explanation:

5 0

3 years ago