Answer:
10.07 L is the volume for the produced N₂
Explanation:
This is a question for the Ideal Gases Equation:
P . V = n . R . T
In STP conditions, the pressure is 1 atm and the T° is 273K
Let's determine the moles of produced N₂ by the decomposition of TNT
The reaction is:
2 C₇H₅(NO₂)₃ (s) → 7 C (s) + 7 CO (g) + 3 N₂ (g) + 5 H₂O (g)
We convert the mass to moles (mass / molar mass)
68.2 g . 1 mol / 227.13 g = 0.300 moles
Ratio is 2:3. 2 moles of TNT can produce 3 moles of N₂
Then, 0.300 moles will produce (0.300 . 3) / 2 = 0.450 moles
We replace data:
1 atm . V = 0.450 mol . 0.082 L.atm/mol.K . 273K
V = (0.450 mol . 0.082 L.atm/mol.K . 273K) / 1 atm
V = 10.07 L
The name or type of covalent bond in which electrons are shared unequally is a polar covalent bond.
The case is acidic since calculated pH is below 7 that is 2.3
The hydroxide and hydrogen ion levels in a solution are the sources for calculating pOH and pH levels, respectively, and are the basis of whether a solution is acidic or basic
[H₃O+]=5.3×10⁻³M
To determine the hydroxide ion concentration, we use:
[OH−][H3O+]=1×10⁻¹⁴
We isolate the hydroxide ion concentration:
[OH−]=1×10−145.3×10⁻³M
Solving this, we obtain:
[OH−]=1.9×10−¹²M
We can determine whether the solution is acidic or basic by calculating the pH level:
pH=−log[H3O+]
We substitute in the hydronium ion concentration given:
pH=−Log(5.3×10−3)pH=2.3
Since the pH is below 7, the solution is acidic
Learn more about hydroxide ion here-
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Answer:
The copper oxide can then react with the hydrogen gas to form the copper metal and water. When the funnel is removed from the hydrogen stream, the copper was still be warm enough to be oxidized by the air again.
Explanation:
Percent yield or yield is mathematically defined as:
Yield = Actual amount / Theoretical amount
So to solve the yield, let us first calculate the
theoretical amount of POCl3 produced. The balanced chemical reaction for this
is:
6 PCl5 + P4O10 ---> 10 POCl3
Since P4O10 is stated to be supplied in large amount, then
PCl5 becomes the limiting reactant.
So we calculate for POCl3 based on PCl5. To do this let us
convert the amount into moles: (molar mass PCl5 = 208.24 g/mol)
n PCl5 = 42.66
grams / (208.24 g/mol)
n PCl5 = 0.205 mol
Now based on the
stoichiometric ratio of the reaction:
<span>n POCl3 = 0.205 mol (10
POCl3 / 6 PCl5)
n POCl3 = 0.3414 mol POCl3</span>
Converting to mass (molar
mass POCl3 = 153.33 g/mol)
m POCl3 = 0.3414 mol (153.33 g/mol)
m POCl3 = 52.35 g
Calculating for yield:
Yield = 47.22 g/ 52.35 g
Yield = 0.902
<span>%Yield = 90.2 % (ANSWER)</span>
