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Sholpan [36]
3 years ago
5

This question is asking what the value of g(5) is please answer and explain this cause don’t understand functions at all!!

Mathematics
1 answer:
frosja888 [35]3 years ago
6 0
Short Answer: g(x) = -3x This is a teaching question. 
Remark

Define and describe f(x)
f(x) is read as y is dependent of x. The notation of f(x) with some exceptions is the same thing as y. What it stands for and what it can be used for is to tell you want value x can have if you want a  specific value for x. 

Suppose you are given 
y = x + 2

Then suppose there is another statement above it
Let x = 5
y = x + 2
y = 5 + 2
y = 7

Instead of writing the top statement
Let x = 5
You use the shorthand
f(5) = x + 2
f(5) = 5 + 2
f(5) = 7.

So what does all this come down to. It is just a short way of writing Let x = ?
f(?) is what x will equal. x will become ?. 

Your Question.
Remember that f(x) tells you what x becomes
f(5) means that x = 5.
Is that more than 4 or is that less than 4? It's a serious question. 
Of course 5 is greater than 4. So that means that g(x) = - 3x. You don't have to do anything. Just read it.
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Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

H_0: p = 0.04

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

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The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

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This means that \mu = 0.04, \sigma = \sqrt{0.04*0.96}

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that n = 20, X = 0.1

Value of the test statistic:

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z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}

z = 1.37

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

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The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

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