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Daniel [21]
3 years ago
7

___Al+NaOH=>__Na3AlO3+H2

Chemistry
1 answer:
MaRussiya [10]3 years ago
8 0

Explanation:

<em><u>2Al + 2NaOH + 6H2O → 2Na[Al(OH)4] + 3H2</u></em>

<em><u>...</u></em>

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How many grams of O2 gas are in a 3700 mL container at a pressure of 775 mmHg at 33oC?
Zina [86]

Answer:

4.8 grams

Explanation:

Use PV=nRT

P: 775 mmHg (divide by 760 mmHg to get atm)  -> 1.02 atm

V: 3700 mL (divide by 1000 to get L)  -> 3.7L

n: ?

R: (a constant) 0.0821L * atm/k *mol

T: 33 C (add 273 to get K)  -> 306K

Move equation so n is on the side: PV/RT = n. Plug the numbers into the equation.

\frac{1.02atm * 3.7L }{306K} * \frac{K * mol}{0.0821L *atm} = 0.15 mol

Then, convert moles to grams using the molar mass of O2 which is 32g/mol.

0.15 mol * \frac{32g}{mol}= 4.8g

5 0
2 years ago
Which reaction is an example of an endothermic reaction?
Tasya [4]

Answer:

These examples could be written as chemical reactions, but are more generally considered to be endothermic or heat-absorbing processes: Melting ice cubes. Melting solid salts. ... Converting frost to water vapor (melting, boiling, and evaporation, in general, are endothermic processes.

Explanation:

8 0
4 years ago
Read 2 more answers
At 300 K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm.
kirill [66]

Answer:

A. 0525.

B. 0.3483 atm.

C. 0.3890.

Explanation:

A.

Molar mass of Benzene =

(12*6) + (1*6)

= 78 g/mol.

Number of moles of Benzene = mass/molar mass

= 50/78

= 0.641 moles.

Molar mass of n-hexane =

(12*6) + (1*14)

= 86 g/mol.

Number of moles of n-hexane = mass/molar mass

= 50/86

= 0.581 moles.

Total moles of the solution = number of moles of Benzene + number of moles of n-hexane

= 0.641 + 0.581

= 1.222 moles

Mole fraction is the number of moles of a particular substance in a solution divided by the total number of moles of substances in the solution.

Mole fraction of Benzene = 0.641/1.222

= 0.525.

B.

Vapour Pressure of a solution is the amount of pressure that the vapour exert on the liquid solvent when they are in equilibrium and at a certain temperature.

Uaing Raouit's law and Dalton's law,

Raoult's law states that the the partial pressure of a solution is directly proportional to the mole fraction of the solute component.

Dalton's law states that the total pressure of a solution is the sum of its individual partial pressure.

Uaing Dalton's law,

Psol = Pbenzene + Pn-hexane

= 0.1355 + 0.2128

= 0.3483 atm

C.

Using Raoult's equation, Mole fraction of Benzene = P°benzene/Psol

= 0.1355/0.3483

= 0.3890

4 0
3 years ago
I’ll mark u brainliest!!
statuscvo [17]
A. Strong acids have a high ionization.
5 0
2 years ago
Read 2 more answers
3. Using the periodic table,
riadik2000 [5.3K]

Answer:

79.904 u for bromine

24.305 u

Not really sure what the 3rd question is asking

Explanation:

4 0
4 years ago
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