Answer:
Two conversion factors:
Explanation:
You can create two possible <em>conversion factors</em>, one to convert from mL to L, and one to convert from L to mL
<u />
<u>a) From mL to L</u>
To convert mL to L you need to multiply by a conversion factor that has mL on the denominator and L in the numerator.
Your starting point is: 
Then, divide both sides by 1,000mL (this will be on the denominator of the fraction);
<u>b) From L to mL</u>
Divide both sides by 1 L:
Sulfur-32 Information
This element is absorbed by plants from the soil as sulphate ion. Sulfur has 23 isotopes, 4 of them are stable. Sulfur is used in matches, gunpowder, medicines, rubber and pesticides, dyes and insecticides.
<h3>Which isotope of sulfur contributes the least to its mass number?</h3>
Sulfur (16S) has 23 known isotopes with mass numbers ranging from 27 to 49, four of which are stable: 32S (95.02%), 33S (0.75%), 34S (4.21%), and 36S (0.02%).
<h3>What is the use of Sulphur 35 isotope?</h3>
A radioactive sulfur isotope; a beta emitter with a half-life of 87.2 days; used as a tracer in the study of the metabolism of cysteine, cystine, methionine, and other compounds; also used to estimate, with labeled sulfate, extracellular fluid volumes.
Learn more about isotopes here:
<h3 /><h3>
brainly.com/question/364529</h3><h3 /><h3>#SPJ4</h3>
The reaction equation is:
<span>2CuO(s) + C(s) </span>→ <span>2Cu(s) + CO</span>₂<span>(g)
First, we determine the number of grams present in one ton of copper oxide. This is:
1 ton = 9.09 x 10</span>⁵ g
We convert this into moles by dividing by the molecular mass of copper oxide, which is:
9.09 x 10⁵ / 79.5 = 11,434 moles
Each mole of carbon reduces two moles of copper oxide, so the moles of carbon required are:
11,434 / 2 = 5,717 moles of Carbon required
The mass of carbon is then:
5,717 x 12 = 68,604 grams
The mass of coke is:
68,604 / 0.95 = 72,214 g
The mass of coke required is 7.22 x 10⁴ grams
Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
N + O ---------> NO
Mole ratio of N to NO is 1:1
Mole of 25.0 g of NO = 25/30.01 = 0.833 moles
Equivalent mole of N = 0.833 moles
Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886
The reactivity of a metal is determined by these things.
Firstly, the number of electrons in the outer shell; the fewer the number of electrons in the outer shell, the more reactive the metal.
The number of electron shells also affects reactivity, the more electron shells there are, the more reactive the metal.
