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3 years ago

10

Which equation shows the result of substituting y from the first equation into the second equation for the given system? Y=x+5;

y-2x=2 A.(5-x)-2x=2 B.(x+5)-2x=2 C.(x+5+2x=2 D.(x+5)-2x=0

2 answers:

algol [13]3 years ago

8 0

The answer is b.(x+5)-2x=2

Alika [10]3 years ago

7 0

For E2020 Kids the answer is B. I hope this helps you guys who are using E2020. Have a great day

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When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v squared w

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Answer:

Step-by-step explanation:

The model fo the shell is given by the following equation of equilibrium:

$\Sigma F = -b\cdot v^{2} - m\cdot g = m\cdot \frac{dv}{dt}$

This first-order differential equation has separable variables, which are cleared herein:

$\int\limits^t_{0\,s} \, dt = -\frac{m}{b} \int\limits^{0\,\frac{m}{s} }_{600\,\frac{m}{s} } {\frac{1}{ v^{2}+\frac{m}{b}\cdot g } } \, dv$

The solution of this integral is:

$t = -\frac{m}{2b}\cdot \left[\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }\right) - \tan^{-1} \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }\right)\right]$

$\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } } \right)=-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)$

$\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\right]$

$v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m} \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m} \right) }\right]$

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oksian1 [2.3K]

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Step-by-step explanation:

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Which of the following is a factor of 24x6 − 1029y3?

amid [387]

Answer:

The answer to your question is only the second and the third are factors.

Step-by-step explanation:

Find the factors of 24x⁶ − 1029y³

First find the prime factors of 24 and 1029

24 2 1029 3

12 2 343 7 Then 24 = 2³3

6 2 49 7 1029 = 7³ 3

3 3 7 7

1 1

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Then

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