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2 years ago

What is the weight of a 4.5 kg mass on Earth?

Physics

1 answer:

swat322 years ago

4 0

Answer:

7.535×10^25 earth mass

Explanation:

for an approximate result,divide the mass value by 9.223e+18

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The sum of all forces acting on an object

Zina [86]

Answer:

The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

Explanation:

put in your own words PLEASE, hope it helps

4 0

2 years ago

A truck accidentally rolls down a driveway for 8.0\,\text m8.0m8, point, 0, start text, m, end text while a person pushes agains

gavmur [86]

Answer:

Explanation:

According to work energy theorem

change in kinetic energy of truck = work done against it

work done against it = force x displacement

= - 850 x 8 = 6800 J

change in kinetic energy of truck = - 6800 J .

energy will be reduced by 6800 J

5 0

3 years ago

An object of mass kg is released from rest m above the ground and allowed to fall under the influence of gravity. Assuming the f

IgorLugansk [536]

Answer:

Explanation:

From, the given information: we are not given any value for the mass, the proportionality constant and the distance

Assuming that:

the mass = 5 kg and the proportionality constant = 50 kg

the distance of the mass above the ground x(t) = 1000 m

Let's recall that:

$v(t) = \dfrac{mg}{b}+ (v_o - \dfrac{mg}{b})^e^{-bt/m}$

Similarly, The equation of mption:

$x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})$

replacing our assumed values:

where $v_=0 \ and \ g= 9.81$

$x(t) = \dfrac{5 \times 9.81}{50}t+\dfrac{5}{50} (0 - \dfrac{(5)(9.81)}{50}) (1-e^{-(50)t/5})$

$x(t) = 0.981t+0.1 (0 - 0.981) (1-e^{-(10)t}) \ m$

$\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}$

So, when the object hits the ground when x(t) = 1000

Then from above derived equation:

$\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}$

$1000= 0.981t-0.981(1-e^{-(10)t}) \ m$

By diregarding $e^{-(10)t} \ m$

$1000= 0.981t-0.981$

1000 + 0.981 = 0.981 t

1000.981 = 0.981 t

t = 1000.981/0.981

t = 1020.36 sec

7 0

2 years ago

As current increases in an electromagnet’s coil, the strength of the magnet field _______(increases, decreases, remains the same

Ahat [919]

Answer:

increases

Explanation:

because as when the electimagnatics coul coul starts to increase the magnetic field also increases

7 0

2 years ago

A particle moves along the x-axis according to the equation x(t)= 2.9- 4.1t^2 m. what are the velocity (in m/s) and acceleration

kherson [118]

From the equation you can tell that your particle is moving with a costant acceleration. The generic movement equation is $x= x_0 +v_0 t + \frac 1 2 a t^2$ , and velocity is given by $v= v_0 + at$ with $x_0$ and $v_0$ being the position and velocity at $t=0$ s.

By comparing the two acceleration is costant, and it's the same at t=0, t=3.0, or t=3000s, and is $\frac 1 2 a = 4.1$ . Velocity comes from the second formula, you found the acceleration in the previous step, and you just have to plug 0 for $v_0$ , the value of a you found, and 6 s for t.

7 0

3 years ago