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nlexa [21]
2 years ago
6

The gravitational acceleration on Earth is 9. 8 m/s2. What is the weight of a car on Earth (to the nearest whole number) if it h

as a mass of 1360 kg? 14 N 139 N 1333 N 13,328 N.
Physics
1 answer:
astraxan [27]2 years ago
6 0

Hi there!

Recall the equation for weight.

W = Mg

W = Weight (N)

M = Mass (kg)
g = acceleration due to gravity (m/s²)


The weight of an object depends upon its MASS and the strength of the GRAVITATIONAL field. We can solve for weight:

W = 1360 * 9.8 = \boxed{13,328 N}

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A crate is acted upon by a net force of 100N. An acceleration of 5.0 m/s^2 results. What is the rate of the crate?
andreev551 [17]
Is there any other information given? I don't think you can solve this without a time
6 0
3 years ago
Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

7 0
3 years ago
Are switches connected in series or parallel with the devices they control?
andrezito [222]

In some unusual applications of unusual components, I can think of unusual electric circuits where a switch may be connected in parallel with a device in order to control it.  

But I'm sure this is not what's intended in a question on the high-school level.  

Until you get in a situation with tricky applications in a tricky circuit, your switches will always be connect <em>in series</em> with the devices they control.

3 0
3 years ago
A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exe
PtichkaEL [24]

Answer:

The pressure exerted by the brick on the table is 18,933.3 N/m².

Explanation:

Given;

height of the brick, h = 0.1 m

density of the brick, ρ = 19,300 kg/m³

acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

P = ρgh

P = (19,300)(9.81)(0.1)

P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².

4 0
3 years ago
Tech A says that as engines gain miles, the spark plug gap increases, which raises the ignition system’s available voltage. Tech
Ugo [173]

Answer: Tech A is correct

Explanation:

Every vehicle has ignition system and without this system,it will not work. The battery of everything vehicle contain energy that start the vehicle and ignore it to start working. Electrical current move from the vehicle's battery and get to the induction coil, the induction coil increases the voltage in it so that the plug will be ignited. The spark plugs produce fire. The spark plug is connected to the ignition system. Once voltage is produced from the induction coil, electrical impulses move from induction coil to insulated plug wires. The spark plug need a very high voltage from the small voltage battery. Once the high voltage exceed the dielectric strength of the gases, spark jump the gap between the plug's fire end.

8 0
3 years ago
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