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Neporo4naja [7]
3 years ago
7

Describe the interactions that are disrupted between water molecules when salt is added to the water that would affect the boili

ng point.
Chemistry
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

The correct answer is that the polar bonds are altered and the boiling point is elevated.

Explanation:

In the case of table salt mixed with water, the sodium (Na) and chlorine (Cl) atoms initially bound together in the form of a crystal are dissolved by the water molecules.

The sodium and chlorine ions are mixed uniformly with the surrounding water molecules, so that the salt dissolves in the water, forming a homogeneous mixture. Water is a polar compound, so it easily dissolves polar substances such as salts.

This raises the boiling point of the water, as it is more difficult to break the bonds of the solution.

Have a nice day!

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did u ever get the answer ? I’m also on k12 stuck on this lol

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Which of the following statements is/are true? For the false statements, correct them.
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3 years ago
Calculate the concentration (M) of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to
Luda [366]

The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:

m_1v_1 = m_2v_2

Where m_1 is the molarity before dilution, v_1 is the volume before dilution, m_2 is the molarity after dilution, and v_2 is the volume after dilution.

In this case, m_1 = 0.774 M, v_1 = 10.0 mL, v_2 = 100 mL.

m_2 = m_1v_1/v_2

     = 0.774 x 10/100

      = 0.0774 M

Thus, the new concentration of the sodium sulfide solution would be 0.0774 M.

Mole of the final solution: 0.0774 x 0.1 = 0.00774 mol

Sodium sulfide formula = Na_2S ---> 2Na^+ + S^{2-

Equivalent mole of sodium ion = 0.00774 x 2

                                                    = 0.01548 mol

The concentration of sodium ions = mol/volume

                                                  = 0.01548/0.1

                                                  = 0.1548 M

In other words, the concentration of the sodium ions in the diluted solution would be 0.1548 M.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

6 0
1 year ago
My teacher has asked me to research the amount of energy released through combustion on a natural gas stove and to show how the
Masteriza [31]

Answer:

I wouldn't be entirely sure, but I believe your teacher means the energy as in being transferred such as when you are cooking something and how it varies.  Avocado oil has a higher content of unsaturated fats. Olive oil contains a high ratio of monounsaturated fatty acids to satured fatty acids. Avocado oil has a very high smoke point, between 480°F and 520°F (270°C). The oil is a good choice for stir-fry recipes and other high-temperature cooking. It is ideal for searing meats and frying in a wok.

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Extra virgin olive oil has a low smoke point, around 220°F. It is unsuitable for high-temperature cooking or frying.

You should keep in mind that when you heat oil to its smoking point, it loses its nutrient content and becomes dangerous for consumption. It leads to the formation of toxic compounds and harmful free radicals which are carcinogenic.

Explanation:

All oils are different.  The "smoke point" of the oil is how the oil is classified.  The smoke point is the temperature at which the oil begins to smoke.  It begins to burn at this point and it can be a fire hazard.  The "flash point" is the temperature at which the oil ignites.

Your welcome

3 0
3 years ago
Select the correct relationship among the concentrations of species present in a 1.0 M aqueous solution of the weak acid represe
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Answer:

D

Explanation:

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Being a weak acid, there is maximum concentration of water molecules followed by that of undissiociated acid.

Hence, for this solution, the concentration of ions in solution follows the order;

[H2O] > [HA] > [A-] ~ [H3O ] > [OH-]

8 0
3 years ago
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