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liq [111]
3 years ago
5

You have three molecules of glucose (3C^6H^12O^6). How many carbon atoms do you have?

Chemistry
2 answers:
allsm [11]3 years ago
5 0
You have 6 carbon atoms in glucose. Multiply by 3 and you get 18.
shutvik [7]3 years ago
3 0
Each molecule of glucose has 6 Carbon atoms, so 3 molecules would be 3*6 Carbon atoms, or 18 in total.
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In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu
Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of <em>two different elements</em>.

Thus, each molecule has permanent <em>bond dipoles</em>.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0
3 years ago
A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema
timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 5.76 L
  • T1= 22 °C= 295 °K (Being 0°C=273°K)
  • V2=17.28 L
  • T2=?

Replacing:

\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}

Solving:

T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}

T2= 885 °K = 612 °C

<u><em>The final temperature was 612 °C</em></u>

5 0
3 years ago
Can a scientific theory turn into a scientific law?
beks73 [17]
Possibly, Yes if it is proven
4 0
3 years ago
Read 2 more answers
a quantity of zinc reacts with sulfuric acid and produces 0.10g of hydrogen. how many particles of zinc are required socratic.or
alekssr [168]

Answer:

grams of zinc required = 3.24 g

Particles of zinc required = 2.99\times 10^{22}

Explanation:

Given that:-

Mass of hydrogen gas produced = 0.10 g

Calculation of the moles of H_2 as:-

Mass = 0.10 g

Molar mass of H_2 = 2.016 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.10\ g}{2.016\ g/mol}

Moles= 0.0496\ mol

According to the reaction shown below:-

Zn+H_2SO_4\rightarrow ZnSO_4+H_2

1 mole of hydrogen gas is produced when 1 mole of zinc reacts

So,

0.0496 mole of hydrogen gas is produced when 0.0496 mole of zinc reacts

Moles of Zinc required = 0.0496 moles

Molar mass of zinc = 65.38 g/mol

mass= Moles*Molar mass = 0.0496\ moles\times 65.38\ g/mol=3.24\ g

Also, 1 mole of Zinc contains 6.023\times 10^{23} particles

0.0496 mole of Zinc contains 0.0496\times 6.023\times 10^{23} particles

Particles of zinc required = 2.99\times 10^{22}

6 0
3 years ago
Which element in period 3 has both metallic and non metalik properties​
Andrei [34K]

Answer:

Si is the answer I hope this help

6 0
3 years ago
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