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3 years ago

According to the concept of the tragedy of the commons, what happens to shared resources over time?

Chemistry

2 answers:

mario62 [17]3 years ago

6 0

Another APEX Answer:

They are overused.

Maslowich3 years ago

5 0

I would believe the answer to this question is D. According to the concept of the tragedy of the commons, shared resources are used by more than one organism. Due to the large consumption of shared resources they start to be fewer and fewer in number and over time if we are not careful they will be depleted.

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At 60°c, the ion-product constant of water, kw, is 9.25 × 10–14 . what is the ph of pure water at 60°c ?

Rus_ich [418]

Answer:

6.517.

Explanation:

It is known that for pure water: [H₃O⁺] = [OH⁻], so water is neutral.

It also is known that:

Kw = [H₃O⁺][OH⁻] = 9.25 x 10⁻¹⁴.

∵ [H₃O⁺] = [OH⁻].

∴ [H₃O⁺]² = 9.25 x 10⁻¹⁴.

∴ [H₃O⁺] = √(9.25 x 10⁻¹⁴) = 3.041 x 10⁻⁷ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(3.041 x 10⁻⁷) = 6.517.

3 0

3 years ago

What are even covalent chlorides? Question D

liq [111]

Answer:

The chlorine atom (or atoms) is covalently bonded by a shared pair of electrons to the other element.

Explanation:

4 0

3 years ago

What is the molality of an aqueous KCl solution with a mole fraction of KCl, XKCl = 0.175? (The molar mass of KCl = 74.55 g/mol

NARA [144]

Answer:

The molality of the KCl solution is 11.8 molal

Explanation:

Step 1: Data given

Mol fracrion KCl = 0.175

Molar mass KCl = 74.55 g/mol

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mol fraction H2O

mol fraction H2O = 1 - 0.175 = 0.825

Step 3: Calulate mass of H2O

Suppose the total moles = 1.0 mol

Mass H2O = moles H2O * molar mass

Mass H2O = 0.825 * 18.02 g/mol

Mass H2O = 14.87 grams = 0.01487 kg

Step 4: Calculate molality

Molality KCl = 0.175 / 0.01487 kg

Molality KCl = 11.8 molal

The molality of the KCl solution is 11.8 molal

5 0

3 years ago

Can anyone pls summarize this for me

kotykmax [81]

Answer:here is the answer

Scholarcy, the online article summarizer tool, reads your research articles, reports and book chapters in seconds and breaks them down into bite-sized sections – so you can quickly assess how important any document is to your work.

Explanation:

8 0

3 years ago

Read 2 more answers

If 200 grams of water is to be heated from 24.0oC to 100.0oC to make a cup of tea, how much heat must be added?

aksik [14]

According to this formula:

Q = M*C*ΔT

when we have M ( the mass of water) = 200 g

and C ( specific heat capacity ) of water = 4.18 J/gC

ΔT (the difference in temperature) = Tf - Ti

= 100 - 24

= 76°C

So by substitution:

Q = 200 g * 4.18 J/gC * 76 °C

= 63536 J

∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J

3 0

4 years ago