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3 years ago

How can the rescue workers get enrgy to the batteries in their equipment during rescue missions.

Chemistry

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

a generator that allows them to convert kinetic energy into potential energy

Explanation:

Rescue workers can accomplish this by using a generator that allows them to convert kinetic energy into potential energy. Such as a crank generator, with these, they spin a crank with their hands and the generator takes that kinetic energy that is building up through the work that the rescuer is exerting and converts it to potential electric energy that can properly be used to provide energy to the batteries for their equipment. This is what is generally used for situations such as what rescuers go through when there is no electricity around.

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Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)

Stels [109]

<span> Au</span>₂(SeO₄)₃

O = -2 × 4 = -8
Se = + 6
So,
(+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3

-2 ₓ 3 = -6
Means,
Au₂ + (-6) = 0

Au₂ = +6
Or,
Au = 6 / 2

Au = +3
Result:
Au = +3
Se = +6
O = -2

Ni(CN)₂

Cyanide (CN⁻) contains -1 charge,
So,
N = -3
C = +2
Then,
Ni + (-1)₂ = 0

Ni - 2 = 0
Or,
Ni = +2
Result:
N = -3
C = +2
Ni = +2

6 0

4 years ago

A sample of potassium phosphate octahydrate (K3PO4•8H2O) is heated until 7.93 grams of water are released. How many grams did th

Gekata [30.6K]

The original sample of potassium phosphate octahydrate had a mass of 19.6 grams. When it was heated, it released 7.93 grams of water.

Further Explanation:

For every mole of the compound potassium phosphate octahydrate, there are 8 moles of water of hydration which can be removed from the crystal by heating without altering the chemical composition of the substance.

To determine how much original sample was used, the amount of water released upon heating may be used as well as the mole ratio of the water of hydration with the compound itself following the steps below:

Convert mass of water released to moles.
Use the mole ratio of water of hydration to the compound (8 mol water for every mol of potassium phosphate octahydrate) to get the moles of original sample.
Convert the moles of original sample to grams.

STEP 1: Convert 7.93 g water to moles.

$moles \ of\ H_{2}O \ = 7.93 \ g \ H_{2}O \ (\frac{1 \ mol \ H_{2}O}{18.00 \ g \ H_{2}O})\\\boxed {moles \ of \ H_{2}O \ = 0.4406 \ mol}$

STEP 2: Calculate the moles of original sample using the mole ratio: 1 mol K3PO4 8H2O : 8 mol H2O.

$moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.4406 \ mol \ H_{2}O \ (\frac{1 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ }{8 \ mol \ H_{2}O})\\\\\boxed {moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.0551 \ mol}$

STEP 3: Convert the moles of original sample to mass.

$mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 0.0551 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ (\frac{356.3885 \ g}{1 \ mol\ K_{3}PO_{4}\ 8H_{2}O})\\ mass \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 19.637 \ g$

Following the significant figures of the given, the final answer should be:

$\boxed {mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 19.6 \ g}$

Learn More:

Learn more about water of hydration brainly.com/question/6053815
Learn more about mole conversion brainly.com/question/12979299
Learn more about percent hydrate brainly.com/question/12398621

Keywords: water of hydration, hydrate

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3 years ago

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oee [108]

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Gestalt psychology focuses on _____.

jok3333 [9.3K]

Answer:

the brain's ability to memorize information

Explanation:

Gestalt psychology provides a holistic perception to how the brain tends to deal with information it picks. The belief is that the whole is greater than the individual parts. Gestalt is a German word which means whole.

Psychologists that subscribes to this school of thought believes that the brain generally relates with events by creating a complete perceived view of such. For example, christmas lights are pictured as moving because its easier for the brain to relate with such rythm in that way. This helps the brain memorize a piece better than looking at individual relationship between the parts.

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4 years ago

Can someone help me, please

Gnesinka [82]

What do you need help with

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3 years ago

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