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nevsk [136]
2 years ago
11

Energy naturally moves from a heat source to a heat ______.

Chemistry
1 answer:
guapka [62]2 years ago
5 0
D, none of the above
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1. An electric power plant uses energy from burning coal to generate steam at 450 °C. The plant is cooled by 20 °C water
kap26 [50]

Answer:

Explanation:

Efficiency of the electric power plant is e=1-\frac{T_{2}}{T_{1}}

Here Temperature of hot source T_{1} = 450^{o}C=450+273=723 K

and Temperature of sink T_{1} = 20^{o}C=20+273=293 K

Hence the efficiency is  e=1-\frac{293}{723}=0.5947=59.47%

Now another formula for thermal efficiency Is

e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found

W is the of work done and W = QI -Q2

Hence Frome_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

W=e(Q_{1})=(0.5947)(100)=59.47MJ

Hence the of heat transferred to the river Is Q_{2} -W = (100 -59.47=40.53

6 0
3 years ago
How many liters are there in 3.49 x 10^22 molecules of O2 at STP
Sholpan [36]

Answer:

I think 767.8

Explanation:

I first did 10 times 22 bc that little carrot sign means squared so I did 10 times 22 and that equaled 220, then I did 3.49 times 220 and that is the answer which is 767.8

5 0
3 years ago
0.44 mL/min to microliters per second
SashulF [63]

Answer:

7 μl /s

Explanation:

Given data:

0.44 mL/min

μl /s = ?

Solution:

First of all we will convert the mL/min to mL/s.

we will divide the given value by 60.

0.44/60

0.007 mL/s

Now we will convert the mL/s to μl /s.

we will multiply the value with 1000.

0.007 × 1000

7 μl /s

7 0
2 years ago
Which of these statements best describes a similarity between combustion and respiration?
hodyreva [135]
Both respiration and combustion can produce carbon dioxide. Therefore, of the answers in your list only the third one is correct.
8 0
2 years ago
Read 2 more answers
Why is it important for lens makers to know then density of the glass they are using??
vlada-n [284]
The density of a glass helps determine the weight of the optical assembly and, along with lens diameter, becomes critical for weight sensitive applications. 
6 0
2 years ago
Read 2 more answers
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