Answer:
What I came up with was D equaling out to be 42
Explanation:
Im assuming you just do the math
A. 3.5 x 104 = 364
B. 2.4 x 103 = 247.2
C. 1.4 x 10^2_2 = 280
D. 4.9 x 10-7 = 42
I hope I helped.
Answer:
The mass of PbSO4 formed 15.163 gram
Explanation:
mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625
mole of Na₂SO₄ = 2 x 0.025 = 0.05
Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃
( Mole/Stoichiometry )
= 0.0625 = 0.05
From (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.
Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄
= 0.05 x 303.26 g
= 15.163 g
Answer:
Groups show similar chemical properties about the elements
Explanation:
The periodic table is divided into groups and periods. Groups are vertical while periods are horizontal.
All elements in the same group possess the same number of outermost shell electrons. This number of outermost shell electrons controls the reactivity of the elements in the group.
Hence, groups show similar chemical properties of the elements in them, Groups separate elements into families which assist in the speedy study of elements.
Answer;
= 0.054 kg or 54 g
Explanation;
Using the equation; Q = mcΔT where Q is the quantity of heat transferred, m is the mass, c is specific heat of the substance, ΔT is delta T, the change in temperature.
ΔT = 75 - 20 = 55 C.
Solve the equation for m
m = Q/ cΔT
Mass = 12500 / (55 × 4200)
= 0.054 kg or 54 g
Answer:
the value of the equilibrium constant Kp for this reaction is 0.275
Explanation:
Step 1: Data given
Pressure HCl at the equilibrium = 18.0 atm
Pressure H2 at the equilibrium = 25.4 atm
Pressure Cl2 at the equilibrium = 46.4 atm
Step 2: The balanced equation
H2(g) + Cl2(g) → 2 HCl(g)
Step 3: Calculate the value of the equilibrium constant Kp for this reaction
Kp = (pHCl)² / (pH2*pCl2)
Kp = 18.0² / (25.4 * 46.4)
Kp = 324 / 1178.56
Kp = 0.275
the value of the equilibrium constant Kp for this reaction is 0.275