Answer:
Heat travels faster in solids.
Heat travels slower in gases.
Explanation:
The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
<h3>What is Limiting reagent ?</h3>
The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
Given chemical equation in balanced form ;
2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).
According to the Chemical equation ;
- The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.
But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.
- 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react
As 80 g NaOH produces 106 g of Na₂CO₃.
Therefore 5 g NaoH will produce ;
106 / 80 x 5 = 6.625 g
Learn more about limiting reagent here ;
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Answer:
yes
Explanation:
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The choices are true about the characteristic of a strong base, except for it having a concentration of above 1.0 M. Therefore, the answer is letter A. The concentration of the base is not a very important as to how strong really the base is.
Answer:
100.5 ≈ 101
Explanation:
Km for S1 = 2.0 mM
Km for S2 = 20 mM
Given that : S1 = S2 = hence Vmax for either S1 or S2 can represent
The Vmax can be calculated using the data Given and equation below
Vo = Vmax [s] / ( Km + [s] ) ------ (1)
Vo = 0.5
[s] = 0.1 mM
km = 20 mM
making Vmax subject of equation 1
Vmax = 0.5 ( 20.1 mM) / (0.1 mM )
= 100.5 ≈ 101
