2 years ago

The molar solubility of x2s in pure water us 0.0395

1 answer:

7 0

The Ksp shows the extent of dissolution of a solute in solution. The Ksp of the solution is 2.5 * 10^-4.

The Ksp is an equilibrium constant that is usd to show the extent of solubility of a solute in solution.

The equation for the solution of X2S is;

X2S(s) ⇄2X^+(aq) + S^2-(aq)

Ksp = [2s]^2 [s]

Since s = 0.0395 M

Ksp = 4s^3

Ksp = 4[0.0395 ]^3

Ksp = 2.5 * 10^-4

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