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2 years ago

The molar solubility of x2s in pure water us 0.0395

1 answer:

7 0

The Ksp shows the extent of dissolution of a solute in solution. The Ksp of the solution is 2.5 * 10^-4.

The Ksp is an equilibrium constant that is usd to show the extent of solubility of a solute in solution.

The equation for the solution of X2S is;

X2S(s) ⇄2X^+(aq) + S^2-(aq)

Ksp = [2s]^2 [s]

Since s = 0.0395 M

Ksp = 4s^3

Ksp = 4[0.0395 ]^3

Ksp = 2.5 * 10^-4

Learn more about Ksp: brainly.com/question/27132799

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What factors affect the rate of dissolving a solid in a liquid? Explain...

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stirring, temperature, and particle size

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3 years ago

Three blocks are shown: Three blocks are shown. Block A has mass 3 kilograms, length 6 centimeters, height 4 centimeters, and wi

dsp73

Answer:

Block A has the greatest density.

Explanation:

Three blocks are shown: Three blocks are shown.

Block A has mass 3 kilograms, length 6 centimeters, height 4 centimeters, and width 2 centimeters.

Block B has mass 1 kilograms, length 6 centimeters, height 2 centimeters, and width 4 centimeters.

Block C has mass 2 kilograms, length 2 centimeters, height 6 centimeters, and width 4 centimeters.

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- Block A has the greatest density.

- Block B has the greatest density.

- The density of Block A is equal to the density of Block B.

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1 year ago

Any time an atom transfers or shares an electron a is formed

polet [3.4K]

Anytime an atom shares or transfers electrons a bond is formed, sharing= covalent and transfer= ionic

6 0

3 years ago

Which are factors scientists use to classify orders of soil?

Sergio039 [100]

Answer:

Soils are a function of the five soil-forming factors: climate, organisms, relief, parent material, and time. Each of these factors range on a continuum, so the different soils of the world number in the thousands. Soil scientists recognize 12 major orders of soils.

Explanation:

8 0

2 years ago

What mass of propane could burn in 48.0 g of oxygen? C3H8 + 5O2 → 3CO2 + 4H2O

Ipatiy [6.2K]

Answer:

Mass = 13.23 g

Explanation:

Given data:

Mass of oxygen = 48.0 g

Mass of propane burn = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 48.0 g/ 32 g/mol

Number of moles = 1.5 mol

now we will compare the moles of propane and oxygen.

O₂ : C₃H₈

5 : 1

1.5 : 1/5×1.5 = 0.3 mol

Mass of propane burn:

Mass = number of moles × molar mass

Mass = 0.3 mol × 44.1 g/mol

Mass = 13.23 g

6 0

2 years ago