The molar solubility of x2s in pure water us 0.0395
1 answer:
The Ksp shows the extent of dissolution of a solute in solution. The Ksp of the solution is 2.5 * 10^-4.
<h3>What is Ksp?</h3>
The Ksp is an equilibrium constant that is usd to show the extent of solubility of a solute in solution.
The equation for the solution of X2S is;
X2S(s) ⇄2X^+(aq) + S^2-(aq)
Ksp = [2s]^2 [s]
Since s = 0.0395 M
Ksp = 4s^3
Ksp = 4[0.0395 ]^3
Ksp = 2.5 * 10^-4
Learn more about Ksp: brainly.com/question/27132799
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