1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alex41 [277]
3 years ago
15

How many moles are in 6.8 x 1023 molecules of NaOH?

Chemistry
2 answers:
MariettaO [177]3 years ago
5 0
My math may be off but i believe 24 moles
hoa [83]3 years ago
5 0

Answer:

The correct answer is: 1.129 mol

Explanation:

Hello! Let's solve this!

The data we have are:

6.8 x 10 ^ 23 molecules of NaOH

Each one mole of substance there are 6.02x10²³ molecules

number of moles: 6.8 x 10 ^ 23 /6.02x10²³ molecules / mol = 1.129 mol

The correct answer is: 1.129 mol

You might be interested in
Which is the term for an ion that has more protons than electrons
murzikaleks [220]

Answer:

The correct answer is cation. See the explanation below, please.

Explanation:

An atom with a net charge, either positive or negative, is called an ion. In the event that an atom loses an electron (or more), that is, it will have more protons than electrons, and its net charge will be positive, it will be called cation. In the opposite direction, if an atom gains electrons, it will have a negative net charge, called anion.

3 0
3 years ago
Please help , science tho. by the way i have to do 5
kap26 [50]

Answer:

850

Explanation:

It's between 840 and 860

8 0
2 years ago
The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,
Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

⇒               =4.08\times 10^{-19} Joule

7 0
3 years ago
How do you solve for the Atomic Mass in chemistry?
loris [4]
Https://www.google.com/search?q=how+to+solve+fir+atomic+mass+in+chemisty&ie=UTF-8&oe=UTF-8&hl=en-us&client=safari#kpvalbx=1
Here is the link to a great video that explains your question nicely, hope this helps.
6 0
4 years ago
Read 2 more answers
The formation constant for the reaction ag (aq) 2nh3(aq) ag(nh3)2 (aq) is kf = 1.7 × 107 at 25°c. what is δg° at this temperatur
anzhelika [568]

The value of ΔG° at this temperature is -18034.18 J/mol

Calculation,

Given information

formation constant (Kf)= 1.7 × 10^{7}

Universal gas constant (R) = 8.314 J/K• mol

Temperature = 25° C = 25 °C + 273 = 300 K

Formula used:

ΔG° = -RT㏑Kf

By putting the valur of R,T, Kf we get the value of ΔG°

ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × 10^{7}

ΔG° = -2494.2㏑ 1.7 × 10^{7} = -18034.18 J/mol

So, change in standard Gibbs's free energy is -18034.18 J/mol

Learn about formation constant

brainly.com/question/14011682

#SPJ4

8 0
2 years ago
Other questions:
  • When an oxygen atom forms an ion, it gains two electrons. Identify the electrical charge of the oxygen ion.
    11·2 answers
  • What elements are in table salt
    12·1 answer
  • How many atoms of phosphorus are in 3.30 mol of copper(II) phosphate?
    14·2 answers
  • What is the ralio of Sr + ions to Brions in a neutral compound?
    13·1 answer
  • What do tissues combine to form?
    5·2 answers
  • Of the following equilibria, only ________ will shift to the right in response to a decrease in volume. N2 (g) + 3H2 (g) 2NH3 (g
    7·1 answer
  • 3. If 90.0 grams of barium chloride react with sulfuric acid, how many
    13·1 answer
  • 4.
    9·1 answer
  • Mixtures of hydrogen and oxygen in varying concentrations can be sparked to produce water. Define mixture and compound, and then
    15·1 answer
  • What is the parent chain of the following compound? a. hexane b. heptane c. octane d. nonane e. decane
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!