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Lerok [7]
3 years ago
13

Which is greater 3L or 300 ML of milk first person to answer gets a brainliest

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0
300 ML Is greater you're welcome :DDDDDDDDD
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Determine the x-intercept of the line whose equation is given:
Nookie1986 [14]
A I think this because I did the math in my head lol
7 0
2 years ago
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HELP ASAP Solve for x. Show or explain your work.
irinina [24]

Answer:

x=4.5

Step-by-step explanation:

From AAA, both triangles in this figure are similar. Therefore, we can set up the following proportion:

\frac{x}{9}=\frac{x+3}{15} or \frac{x}{9}=\frac{3}{6}.

Cross-multiplying, we get:

6x=9(3),\\6x=27,\\x=\frac{27}{6}=\fbox{$4.5$}.

7 0
3 years ago
Which inequality doesn't belong?<br> 5/4≤2 8.5≥0.95 8.5≤7 10.00≤100
NNADVOKAT [17]

Answer:

8.5 < 7

Step-by-step explanation:

8.5 is less than 7.

doesn't verify mathematically.

6 0
2 years ago
A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
3 years ago
Find the equation of a line that passes through the points (-2,-3) and (4,1)
TiliK225 [7]

The equation of the line from give points is y = 2/3x - 5/3.

According to the statement

We have given that the two points which are (-2,-3) and (4,1)

And we have to find the equation of a line that passes through the given points.

So,For this purpose,

First, we need to determine the slope of the line. The slope can be found by using the formula:

m = \frac{(y_2) -(y_1)}{(x_2) -(x_1)}

Where

m is the slope and

Substituting the values from the points in the problem gives:

m = 1 + 3 /4 + 2

m = 4/6

m = 2/3.

And then

Now, we can use the point-slope formula to find an equation for the line. The point-slope formula states:

y - (y_1) = m(x -x_1)

Put the values in it then

y - (-3) = 2/3 (x-(-2))

y +3 = 2/3 (x +2)

3y + 9 = 2x + 4

3y - 2x = 4 -9

3y -2x = -5

3y = 2x - 5

y = 2/3x - 5/3.

So, The equation of the line from give points is y = 2/3x - 5/3.

Learn more about equation of the line here

brainly.com/question/13763238

#SPJ1

4 0
1 year ago
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