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3 years ago

Which situation could be modeled by the expression 13÷5 ?

Mathematics

2 answers:

Alex3 years ago

8 0

Answer: The expression 13÷5 is a fraction. Here the only option that makes sense as per this expression is:

B. Each of 5 cupcakes used 13 pound of sugar. What is the total amount of sugar used?

Therefore the option B is correct

Also please note:

A fraction is a number that represents a part of a whole. It consists of a numerator and a denominator. The numerator represents the number of equal parts of a whole, while the denominator is the total number of parts that make up said whole.

GaryK [48]3 years ago

6 0

Answer:

i believe it is B. im taking this test rn

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3(2a+b) for b=4 and a=a

Kamila [148]

Answer:

I miss the rage

Step-by-step explanation:

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2 years ago

Read 2 more answers

If x2-y2 = 10 and x+y = 5, what is the value of x-y? 2-5?

netineya [11]

Answer:

x-y=2

I don't get why they are asking you what is 2-5. That seems super basic compared to the other question it is with. Since 5-2=3, then 2-5 or -5+2=-3.

Step-by-step explanation:

We are going to use identity x^2-y^2=(x-y)(x+y)

x^2-y^2=10

(x-y)(x+y)=10

(x-y)(5)=10

Since (2)(5)=10, this implies x-y=2.

8 0

3 years ago

Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth

Anika [276]

Answer:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have that the quadratic formula is:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

$2x^{2}-5x-1=0$

$a=2\\b=-5\\c=-1$

Then you have:

$x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}$

3. Therefore, you obtain the following result:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

4 0

3 years ago

Read 2 more answers

Ahmed is solving the following equation for xxx.

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.

Ahmed is solving $2\sqrt[3]{x-7}+11=3$ for x.

His steps were:

$\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}$

Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.

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3 years ago

What is the name of the property of multiplication shown the equation.

Shtirlitz [24]

C- Commutative property.

Explanation: The numbers are flipped around, but still give you the same answer!

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3 years ago