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nirvana33 [79]
3 years ago
13

Help me, please !!!

Mathematics
1 answer:
liubo4ka [24]3 years ago
4 0
I believe the answer is Graph B.  Because, graph B is all over the place making it weak , while graph A is in a row making it a strong correlation.
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Foot pieces you can cut from 5 feet of
Rzqust [24]

Answer:

1p = r

Step-by-step explanation:

You are asking how many 1-foot pieces you can make out of a 5 foot piece of ribbon. You are asking for an equation.

p = the # of pieces

r = the amount of ribbon

So lets try the equation:

1p   = r

1(4) = r

1*4 = 4

4    = r

<h2><u>PLEASE MARK BRAINLIEST!  </u></h2>
7 0
3 years ago
Helppppp plsssssss help
slava [35]
The answer is C. P=h + 11
4 0
3 years ago
HELPP!!! 65 points GIVIN
WITCHER [35]

its 3 1/4 you will thank me later :)

5 0
3 years ago
A spinner numbered 1 through 12 is spun. Find the probability that
anastassius [24]

Answer:

\dfrac{1}{6}

Step-by-step explanation:

Let <em>A</em> be the event of getting an odd number.

<em>P(A)</em> be the probability of getting an odd number.

Total odd numbers here are 6 i.e. \{1,3,5,7,9,11\}

Here, total numbers in the game are 12 i.e \{1,2,3,....,12\}.

Formula for probability of an <em>event E</em> can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}

Let <em>B</em> be the event of getting 11.

<em>P(B)</em> be the probability of getting 11.

Total number of possible cases is 1.

P(B) = \dfrac{1}{12}

P(A \cap B) is the probability that we get 11 and an odd number.

Possible number of cases = 1

P(A\cap B) = \dfrac{1}{12}

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}

Hence, P(B/A) = \dfrac{1}{6}

4 0
3 years ago
Read 2 more answers
You rent an apartment that costs
saul85 [17]
You need to multiply the two numbers. Or you can use long addition.
4 0
3 years ago
Read 2 more answers
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